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3 years ago

5

4.5w = 5.1w - 30 Please help!!!

1 answer:

Lelu [443]3 years ago

6 0

4.5w = 5.1w - 30

4.5w - 5.1w = -30

-0.6w =-30

Divide both sides by -0.6

-0.6w/-0.6 = -30/-0.6

<span>w = 50

</span>I hope this helps.

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1/3 of 12 = 2/3 of<br><br> 1/3 of 12 is the same as 2/3 of

julsineya [31]

Answer:

6

Step-by-step explanation:

since;

1/3 of 12 = 4

so,

(2/3) of x = 4

x=4(3/2)= 6

5 0

3 years ago

Anyone help me with this please!!

Vera_Pavlovna [14]

Answer;
35, 70, and 77

4 0

2 years ago

Find the coordinates of C' after a reflection across the line

iragen [17]

<h3>Answer: (4,2)</h3>

==============================================================

Explanation:

C is at (0,0). Ignore the other points.

Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.

Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"

So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.

All of this is shown in the diagram below.

4 0

3 years ago

HELP PLEASE!!! 10 PTS!!

allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD (Given)

$\angle ADC\cong \angle ACD$

$m\angle ADC=m\angle ACD$

According to the angle sum property, the sum of interior angles of a triangle is 180°.

$m\angle ADC+m\angle ACD+m\angle DAC=180$

$m\angle ACD+m\angle ACD+44=180$

$2m\angle ACD=180-44$

$2m\angle ACD=136$

Divide both sides by 2.

$m\angle ACD=68$

CE bisects ∠ACD.

$m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}$

$m\angle ACE=m\angle DCE=\dfrac{68}{2}$

$m\angle ACE=m\angle DCE=34$

Use angle sum property in triangle CDE,

$m\angle CDE+m\angle DCE+m\angle DEC=180$

$68+34+m\angle DEC=180$

$68+34+m\angle DEC=180$

$102+m\angle DEC=180$

Subtract 102 from both sides.

$m\angle DEC=180-102$

$m\angle DEC=78$

Therefore, the measure of angle DEC is 78°.

6 0

2 years ago

Evan wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn, so he needs no fence

pentagon [3]

Answer: A. A=(1000-2w)*w B. 250 feet

C. 125 000 square feet

Step-by-step explanation:

The area of rectangular is A=l*w (1)

From another hand the length of the fence is 2*w+l=1000 (2)

L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.

Express l from (2):

l=1000-2w

Substitude l in (1) by 1000-2w

A=(1000-2w)*w (3) ( Part A. is done !)

Part B.

To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))

w1=0 1000-2*w2=0

w2=500

Wmax= (w1+w2)/2=(0+500)/2=250 feet

The width that maximize area A is Wmax=250 feet

Part C. Using (3) and the value of Wmax=250 we can write the following:

A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets

3 0

3 years ago