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stiks02 [169]
3 years ago
7

What is the correct answer for 3x+4=9x+4

Mathematics
2 answers:
telo118 [61]3 years ago
4 0

Your answer should be X=0

Andrew [12]3 years ago
3 0

To find the answer you need to get x by itself. First subtract 3x from both sides, you end up with 4=6x+4. Now you need to subtract 4 from both sides, and you get 0=6x. Then you divide both sides by 6 and you get 0=x.

3x+4=9x+4

-3x      -3x

4=6x+4

-4      -4

0=6x

÷6    ÷6

0=x

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The weight is 4000 grams, or 4 kg
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40 x 125% step it out
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Answer:

0.50 or 50%

Step-by-step explanation:

40 x 125 = X

1.25 as a decimal or 125%

40 x 1.25 = 0.50

0.50 --->50%

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2 years ago
Solve for n: n/3 > 66 2/3
Kitty [74]

Answer: The 2 answers are inequality form and interval notation: n>200, and (200, ∞).

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5 0
3 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
Create a Sample Space diagram and work out the probability - There is a 4 sided dice (numbers 1 to 4) and an 8 sided dice (numbe
tester [92]

Answer:

7 / 16

Step-by-step explanation:

Sample space is attached below :

Theoretical Probability of any event A

P(A) = (number of required outcome / Total number of possible outcomes)

Required outcome = sum greater than 7 = 14

Total number of possible outcomes = 32

P(sum greater than 7) = 14 / 32

P(sum greater than 7) = 7 / 16

3 0
3 years ago
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