A hiker sets out to climb a mountain with a 4,000 ft vertical ascent as shown in the diagram below. Ifthe angle of incline, a =
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Answer:
1. So, it's basically y=mx + b, you put the b first like y= 2/3x -1, and the b is negative, so you go down on the y-axis one time and the 2/3x is rise over run 2 is the rise and 3 is the run.
for y=-x -4 you put a denominator for -x like -1/1x you keep the denominator positive.
2. If the 2x is in the incorrect spot you put it on the other side and it's a positive, so you put is as a negative on the other side, so you're left with
-y=-2x-1, but you can't have a sign on them, so you divide it with -1 and on the other side as well, so it comes down to y=2x+1 and if the x doesn't have a denominator you add a one to it, like this y=2/1x+1 and you put the 1 on the y-axis and its a positive so you go up one time and the rise or run is 2/1, so you start at 1 on the y-axis and you rise 2 times, so 3-axis and run 1 time and it's 1-axis.
For the last one ill do it on paper.
Answer:
See below
Step-by-step explanation:
Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.
Permutation can be expressed in math as:
where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.
Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:
Since there are 3 letters total and 3 selected letters to arrange then:
Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:
ABC - 1
ACB - 2
BAC - 3
BCA - 4
CAB - 5
CBA - 6
Notice that if you do visually, you'll get the same answer as the calculation of permutation!
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Combination can be expressed mathematically as:
The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.
Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:
Since there are 3 letters total and 3 selected letters:
Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.