The Answer To your Question is: 33/40
30.949 US Dollar .... for doing this u have to know the currency rates ...
Hope it helps !!!
Part A;
There are many system of inequalities that can be created such that only contain points D and E in the overlapping shaded regions.
Any system of inequalities which is satisfied by (-4, 2) and (-1, 5) but is not satisfied by (1, 3), (3, 1), (3, -3) and (-3, -3) can serve.
An example of such system of equation is
x < 0
y > 0
The system of equation above represent all the points in the second quadrant of the coordinate system.The area above the x-axis and to the left of the y-axis is shaded.
Part B:It can be verified that points D and E are solutions to the system of inequalities above by substituting the coordinates of points D and E into the system of equations and see whether they are true.
Substituting D(-4, 2) into the system
we have:
-4 < 0
2 > 0
as can be seen the two inequalities above are true, hence point D is a solution to the set of inequalities.
Also, substituting E(-1, 5) into the system we have:
-1 < 0
5 > 0
as can be seen the two inequalities above are true, hence point E is a solution to the set of inequalities.
Part C:Given that chicken can only be raised in the area defined by y > 3x - 4.
To identify the farms in which chicken can be raised, we substitute the coordinates of the points A to F into the inequality defining chicken's area.
For point A(1, 3): 3 > 3(1) - 4 ⇒ 3 > 3 - 4 ⇒ 3 > -1 which is true
For point B(3, 1): 1 > 3(3) - 4 ⇒ 1 > 9 - 4 ⇒ 1 > 5 which is false
For point C(3, -3): -3 > 3(3) - 4 ⇒ -3 > 9 - 4 ⇒ -3 > 5 which is false
For point D(-4, 2): 2 > 3(-4) - 4; 2 > -12 - 4 ⇒ 2 > -16 which is true
For point E(-1, 5): 5 > 3(-1) - 4 ⇒ 5 > -3 - 4 ⇒ 5 > -7 which is true
For point F(-3, -3): -3 > 3(-3) - 4 ⇒ -3 > -9 - 4 ⇒ -3 > -13 which is true
Therefore, the farms in which chicken can be raised are the farms at point A, D, E and F.
Answer:
caca
Step-by-step explanation:
Answer:
Solving for x, we could simply say
3x-4=2%28y-2%29-->3x=2%28y-2%29%2B4-->x=%282%28y-2%29%2B4%29%2F3 or x=2%28y-2%29%2F3%2B4%2F3 .
Not wrong, but that could be "simplified" further, and we may need to do that before dividing by y .
It may be better to get rid of those brackets from the start:
3x-4=2%28y-2%29-->3x-4=2y-4-->3x=2y-->x=2y%2F3<-->x=%282%2F3%29y .
Now,
x%2Fy=%282%2F3%29y%2Fy --> highlight%28x%2Fy=2%2F3%29 , for y%3C%3E0
(which in the case of 3x-4=2%28y-2%29 is equivalent to x%3C%3E0 ).
