Equations with absolute value:

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).
How to solve:


Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}
2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6
3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}
4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}
5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Dy/dx, ie., the difference in y divided by the difference in x. If you have two points A and B, sort them in ascending order of x.
dx = 5 - -3 = 8 (x coordinates of B minus x coordinate of A)
dy = -3 - 5 = -8 (y coordinate of B minus y coordinate of A)
dy/dx = -1
So the slope is -1. The equation of the line is y=2-x.
Option C: The solution is 
Explanation:
The given expression is 
We need to solution of the given expression.
The solution of the given expression can be determined by adding the two expressions.
Let us remove the parenthesis.
Thus, we have,

Adding the like terms, we have,

Thus, the solution is 
Hence, Option C is the correct answer.
Note that the equation of the circle is
(x-h)² +(y-k)² =r²
where centre is (h,k)
the equation of the circle based on the information given
(x-3)² +(y-4)² =r²
and the point on the circle (3,-2)
substitute into the equation
(3-3)² +(-2-4)² =r²
r=6 or r=-6
since r is radius, we reject r=-6 since radius must be nonnegative.
the radius is 6