Since he sold it for $75 more,
% Mark Up = Mark Up/ Cost Price * 100%
% Mark Up = 75 / 125 * 100%
= 0.6 * 100% = 60%
Percent Mark Up = 60%.
Hope this explains it.
To find both f(8) and f(-5), we will need to plug in their values for x and solve for each. Then, we can subtract them to find the final answer.
Finding f(8):
f(8) = 3(8) - 2
f(8) = 24 - 2
f(8) = 22
Finding f(-5):
f(-5) = 3(-5) - 2
f(-5) = -15 - 2
f(-5) = -17
Subtracting f(8) and f(-5):
f(8) - f(-5)
22 - - 17
22 + 17
39
Hope this helps!! :)
Answer:
x^3+7x^2−9x−63
Step-by-step explanation:
can i please have brainliest
Udon used hufcimcfinf 8to itfor jvfor
Answer:
a) W₁ = 78400 [J]
b)Wt = 82320 [J]
Step-by-step explanation:
a) W = ∫ f*dl general expression for work
If we have a chain with density of 10 Kg/m, distributed weight would be
9.8 m/s² * 10 kg = mg
Total length of th chain is 40 m, and the function of y at any time is
f(y) = (40 - y ) mg where ( 40 - y ) is te length of chain to be winded
At the beggining we have to wind 40 meters y = 0 at the end of the proccess y = 40 and there is nothing to wind then:
f(y) = mg* (40 - y )
W₁ = ∫f(y) * dy ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy
W₁ = mg [ 40*y |₀⁴⁰ - 1/2 * y² |₀⁴⁰ ⇒ W₁ = mg* [ 40*40 - 1/2 (40)² ]
W₁ = mg * [1/2] W₁ = 10*9,8* ( 800 )
W₁ = 78400 [J]
b) Now we can calculate work to do if we have a 25 block and the chain is weightless
W₂ = ∫ mg* dy ⇒ W₂ = ∫₀⁴⁰ mg*dy ⇒ W₂ = mg y |₀⁴⁰
W₂ = mg* 40 = 10*9.8* 40
W₂ = 3920 [J]
Total work
Wt = W₁ + W₂ ⇒ Wt = 78400 + 3920
Wt = 82320 [J]
