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kherson [118]
3 years ago
9

EASY MATHS PLS HELP​

Mathematics
2 answers:
Goshia [24]3 years ago
5 0

Answer:

The value of x is 5/4 and y is -5.

Step-by-step explanation:

  1. Firstly, you have to make the 1st equation as (1)<em> </em>and make 2nd equation as (2).
  2. Secondly, you have to elimimate one of the variable. I choose to eliminate x in order to get rid of x, I add (1) and (2) together as -4x+4x = 0.
  3. Thirdly, you can solve the value of y. Then after getting y value, you can substitute y value into any equation. I choose to put y value into (1).
  4. Lastly, you can solve the equation to get x value.
  5. THE ANSWER IS OUT !!☝️☝️

Fofino [41]3 years ago
3 0

Answer:

(1.25, - 5 )

Step-by-step explanation:

Given the 2 equations

- 4x + 3y = - 20 → (1)

4x + 2y = - 5 → (2)

Adding the 2 equations term by term will eliminate the x- term

5y = - 25 ( divide both sides by 5 )

y = - 5

Substitute y = - 5 into either of the 2 equations and solve for x

Substituting into (2)

4x + 2(- 5) = - 5, that is

4x - 10 = - 5 ( add 10 to both sides )

4x = 5 ( divide both sides by 4 )

x = \frac{5}{4} = 1.25

Solution is (1.25, - 5 )

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Answer: the answer is c


Step-by-step explanation: 7x=18+3

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                                             x/7=21/7

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7 0
3 years ago
Read 2 more answers
1 7/3 in simplest form
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Howard can type 70 words per minute. At this rate, how many words can he type in<br> 15 minutes?
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Step-by-step explanation:

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2 years ago
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The final exam grade of a mathematics class has a normal distribution with mean of 81 and standard deviation of 6.6. If a random
DochEvi [55]

Answer:

The probability that the average final exam grade of this sample is between 77 and 82

P(77≤ x⁻≤ 82 =  0.8315 or 83%

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given random sample size 'n' = 40

Mean of the normal distribution = 81

Standard deviation of normal distribution = 6.6

Let x₁⁻ = 77

Z_{1} = \frac{x_{1} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{77-81}{\frac{6.6}{\sqrt{40} } }

Z₁ = -3.83

Let x₂⁻ = 77

Z_{2} = \frac{x^{-} _{2} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{82-81}{\frac{6.6}{\sqrt{40} } }

Z₂ = 0.958

<em>The probability that the average final exam grade of this sample is between 77 and 82</em>

P(77≤ x≤ 82) = P( -3.83 ≤x≤0.958)

                    = A( 0.958) + A(3.83)

                   = 0.3315 + 0.4995

                   = 0.8315

<em>The probability that the average final exam grade of this sample is between 77 and 82  = 0.8315 or 83%</em>

4 0
3 years ago
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luda_lava [24]

Answer:

17

Step-by-step explanation:

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