EASY MATHS PLS HELP
2 answers:
Answer:
The value of x is 5/4 and y is -5.
Step-by-step explanation:
- Firstly, you have to make the 1st equation as (1)<em> </em>and make 2nd equation as (2).
- Secondly, you have to elimimate one of the variable. I choose to eliminate x in order to get rid of x, I add (1) and (2) together as -4x+4x = 0.
- Thirdly, you can solve the value of y. Then after getting y value, you can substitute y value into any equation. I choose to put y value into (1).
- Lastly, you can solve the equation to get x value.
- THE ANSWER IS OUT !!☝️☝️
Answer:
(1.25, - 5 )
Step-by-step explanation:
Given the 2 equations
- 4x + 3y = - 20 → (1)
4x + 2y = - 5 → (2)
Adding the 2 equations term by term will eliminate the x- term
5y = - 25 ( divide both sides by 5 )
y = - 5
Substitute y = - 5 into either of the 2 equations and solve for x
Substituting into (2)
4x + 2(- 5) = - 5, that is
4x - 10 = - 5 ( add 10 to both sides )
4x = 5 ( divide both sides by 4 )
x = = 1.25
Solution is (1.25, - 5 )
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Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'
