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Sati [7]
3 years ago
15

If ΔLMN ~ ΔPON, what is MN?

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

MN = 36

Step-by-step explanation:

You can find a ratio between the two triangles based on what you're given.

If LM ~ OP the ratio is 42/14 which = 3

So if MN ~ ON and ON = 12, 12(3) = 36

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Which functions have graphs that are less steep than the graph of f(x)= -4x^2
LiRa [457]
TTese are all parabolas   whose axis of symmetry  is the y  axis. The negative coefficient means they open downwards and the positive mean they open upwards. The higher the absolute value of the coefficient is the greater the slope, so  2x^2 will be steeper than x^2  and -4x^2 will be steeper than - 2x^2.

So h(x) and j(x)  are the answers.
8 0
3 years ago
Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
4 years ago
Do anyone know how to answer this?
ANTONII [103]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
HELP PLZZZZZZZZZZZZZ​
slega [8]

Answer:

i think it is b Because of how the lines are kinda bent

4 0
3 years ago
Read 2 more answers
alex buys a home for $276,400. his home is predicted to increase in value 3.5% each year. What is the predicted value of alex's
Katarina [22]
276400(0.035) = $9674 the equivalent value in dollar for every increase in the house then multiplied by 25. $9674*(25) = $241850 + the current value of Alex's home. $276400+ $241850 = $518250 that would be the value of Alex's home in 25  years. The percentage is (518250-276400)/ 276400 =0.875 *100 = 87.5 % increase in value. I hope this would help.
4 0
3 years ago
Read 2 more answers
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