3 years ago

What is the length of the line segment that begins at (2,6) and ends at (7,6)?

Mathematics

1 answer:

ivolga24 [154]3 years ago

5 0

$\sqrt{(2-7)^2 + (6-6)^2} = \sqrt{25} = 5$

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Answer:

$\sf y = \bold -\frac{2}{5} x -3$

Explanation:

part A identification for slope:

$\sf 2x + 5y = 15$

$\sf 5y = -2x + 15$

$\sf y = \frac{-2x + 15}{5}$

$\sf y = -\frac{2 }{5} x+3$

comparing with slope intercept form: y = mx + b

we can find that here the slope is $\bold -\frac{2}{5}$

part B, solving the equation:

if the line is parallel, then the slope will be same.

given coordinates: ( - 10, 1 )

using the equation:

y - y₁ = m( x - x₁ )

$\sf y - 1 = \bold -\frac{2}{5} (x --10)$

$\sf y = \bold -\frac{2}{5} x -4 + 1$

$\sf y = \bold -\frac{2}{5} x -3$

Extra information:

check the image below. this proves that the line is parallel and passes through point (-10, 1). the blue line is question line and red the answer line.

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