What is the length of the line segment that begins at (2,6) and ends at (7,6)?
1 answer:
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Answer:
the parameter equation of given line is
x= 1+t
y=0+ 2t
z= 9+t
( note: in plane no signs given so we assume + so x+2y+z)
Step-by-step explanation:
A vector perpendicular to the plane a x + b y + c z + d = 0 is given by ⟨ a , b , c ⟩
So a vector perpendicular to the plane x +2 y + z − = 0 is ⟨ 1 , 2 , 1 ⟩
The parametric equation of a line through and parallel to the vector ⟨
a
,
b
,
c
⟩ is
so the parametric equation of our line is
The vector form of the line is