Draw the product formed when the following diene is treated with one equivalent of HCl. Do not show stereochemistry in your answ
er.
1 answer:
Answer:
4-chloro-4-methyl-cyclohexene.
Explanation:
Hello,
On the attached picture you will find the chemical reaction forming the required product, 4-chloro-4-methyl-cyclohexene. In this case, according to the Markovnicov’s rule, it is more likely for the chlorine to be substituted at the carbon containing the methyl radical in addition to the hydrogen to the next carbon to break the double bond and yield the presented product.
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Answer:
- <em><u>3</u></em>
Explanation:
Please, find the image with the pictured molecule for this question attached.
The molecule has one oxygen atom (red) covalently bonded to one hydrogen atom (light grey), one nitrogen atom (blue) covalently bonded to two hydrogen atoms (light grey), and two carbon atoms (dark grey) bonded each to two hydrogen atoms (light grey).
<em>Hydrogen bondings</em> are intermolecular bonds (bonds between atoms of two different molecules not between atoms of the same molecule). The hydrogen bonds are attractions between the positive end of one hydrogen atom and the negative end of a small atom of other molecule (N, O, or F).
Since, nitrogen and oxygen are much more electronegative than hydrogen atoms, you conclude that:
- The two hydrogen atoms covalently bonded to the nitrogen atoms have considerably partial positive charge.
- The hydrogen atom covalently bonded to the oxygen atom also has a a relative large partial positive charge.
So, those are three ends of the molecule that can form hydrogen bonds with water molecules.
The hydrogen bondings are only possible when hydrogen is covalently bonded to N, O or F atoms.
