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boyakko [2]
3 years ago
9

What other simple sugars have the same chemical formula as glucose?

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

The answer to your question is:

Explanation:

Other sugars with the same chemical formula as Glucose:

Sugar            Formula            Description

Glucose         C₆H₁₂O₆            It's the most abundant monosaccharide.

Mannose       C₆H₁₂O₆            It's found in plants and some animals.

Fructose        C₆H₁₂O₆            It's the sugar of fruits.

Galactose      C₆H₁₂O₆            It's found in milk.

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Gallium is a solid metal at room temperature but melts at 29.9 °C. If you hold gallium in your hand, it melts from body heat. Ho
matrenka [14]

Answer:  4.56 Joules

Explanation:-

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m= mass of substance = 2.5 g

c = specific heat capacity = 0.372J/g^0C

Initial temperature  = T_i = 25.0°C

Final temperature  = T_f  = 29.9°C

Change in temperature ,\Delta T=T_f-T_i=(29.9-25.0)^0C=4.90^0C

Putting in the values, we get:

Q=2.5\times 0.372\times 4.90^0C

Q=4.56J

The heat absorbed by gallium must be 4.56 Joules

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3 years ago
Which best describes the act of using senses or tools to gather information? creating a hypothesis making an observation summari
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Answer:

making an observation

Explanation:

its the right answer

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3 years ago
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How many protons and electrons are present in the mg2+ ion? 1. 14 protons, 14 electrons 2. 12 protons, 10 electrons 3. 12 proton
Nataly_w [17]
There are 12<span> protons and </span>10<span> electrons in a </span><span>Mg<span>2+</span></span><span> ion, the normal amount of neutrons is </span>12<span>.</span>
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3 years ago
Calculate the ph of the solution resulting by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh
Aliun [14]

Answer:

1.60.

Explanation:

  • The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
  • The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.

<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>

<em></em>

∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.

∵ pH = - log[H⁺]

<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>

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3 years ago
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