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3 years ago

What other simple sugars have the same chemical formula as glucose?

Chemistry

1 answer:

Usimov [2.4K]3 years ago

8 0

Answer:

The answer to your question is:

Explanation:

Other sugars with the same chemical formula as Glucose:

Sugar Formula Description

Glucose C₆H₁₂O₆ It's the most abundant monosaccharide.

Mannose C₆H₁₂O₆ It's found in plants and some animals.

Fructose C₆H₁₂O₆ It's the sugar of fruits.

Galactose C₆H₁₂O₆ It's found in milk.

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When cyclopentane undergo free-radical substitution with bromine (Br2 /Heat) the product:

Artemon [7]

Explanation:

b. Bromo cyclopentane + HBr

4 0

3 years ago

Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.

STALIN [3.7K]

Answer: Solution A : $[H_3O^+]=0.300\times 10^{-7}M$

Solution B : $[OH^-]=0.107\times 10^{-5}M$

Solution C : $[OH^-]=0.177\times 10^{-10}M$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

$pH=-\log[H_3O^+]$

$pOH=-log[OH^-}$

$pH+pOH=14$

$[H_3O^+][OH^-]=10^{-14}$

a. Solution A: $[OH^-]=3.33\times 10^{-7}M$

$[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M$

b. Solution B : $[H_3O^+]=9.33\times 10^{-9}M$

$[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M$

c. Solution C : $[H_3O^+]=5.65\times 10^{-4}M$

$[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M$

7 0

3 years ago

Write the number of sig. fig. in four numbers given in the sentence below. An (one) octopus has 8 legs. 13 octopi have 104 legs.

Marrrta [24]

Answer:

1, 1, 2, 3

Explanation:

The numbers 1 and 8 both have 1 sig. fig.

The number 13 has 2 sig. figs.

The number 104 has 3 sig. figs.

6 0

3 years ago

Sedimentary rocks are a formed below earths surface as magma b a type of foliated igneous rock c formed by great heat d formed f

Alekssandra [29.7K]

Its either A or C hope one of them helps

5 0

3 years ago

A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253

german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. $\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L$

So, the new volume is 1.45 L.

6 0

3 years ago