Both transition metals and alkali metals are good conductors of heat and electricity, react with water, and are easily oxidized.
<h3>What are alkali metals and transition metals?</h3>
The alkali metals are elements of group 1 which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr). They are also known as the s-block elements because they have their outermost electron in an s-orbital.
The alkali metals are shiny, soft, highly reactive metals and readily lose their outermost electron to create cations with charge +1. They can tarnish rapidly in the air due to oxidation by atmospheric moisture and oxygen.
Transition elements or transition metals are elements that have partially filled d-orbitals. An element having a d-subshell that is partially filled with electrons or can form stable cations with an incompletely filled d orbital.
Any element present in the d-block of the modern periodic table which consists of groups 3 to 12, is considered to be a transition element. For example, the mercury in the +2 oxidation state, corresponds to an electronic configuration of (n-1)d¹⁰. Many paramagnetic compounds are formed by transition metals because they have unpaired electrons in the d orbital.
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First, if you want to get the amount of production from the equation, you need to use the units of mol. So, we need to know the molar mass of C which is 15.75/12=1.31 mol. Then we need to use the less part(O2) to get the production amount which is 0.116 mol. Then we can get the answer in units of g: 0.116*(12+16*2)=5.104 g.
This is true, the force can bring land up at ease
Answer:
Fe.
Explanation:
- The element which is oxidized is the element that losses electrons and its oxidation state be more positive.
- The element which is reduced is the element that gain electrons and its oxidation state be more negative.
<em> Fe goes from + 2 to +3, so, it is the element that is oxidized.</em>
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Answer:- 
.
Solution:- Aspartame is a artificial sweetener with molecular formula 
and it's molecular mass is 294.3 gram per mol.
We have been given with 4.50 mg of aspartame and asked to calculate the moles. For mass to moles conversion we divide the given mass in grams by molar mass.
Since, the mass is given in mg, we need to convert it to g first.
1 mg = 0.001 g
So, 
= 0.00450 g
Now let's calculate the moles on dividing the grams by molar mass as:
=
Hence, are present in 4.50 mg of aspartame.
