Answer:
b)The sample size is large enough to use the normal approximation.
Step-by-step explanation:
In one case when sample size is very large usually, the Normal Distribution can be used to calculate an approximate probability of an event. The explanation of this is expained by the Central Limit Theorem which states that when we have a sample size is large, the sampling distribution of means converge to a normal distribution (approximately) and on this way:
The Binomial distribution can be approximated using a Normal Distribution in case when sample size is large. We can consider a sample size is large when we have these two conditions:
np > 10 and n(1-p)>10,
On this case we can assume the random variable
If we check the conditions:
np=493*0.05=24.65>10
n(1-p)=493*(1-0.05)=468.35>10
So then we can conclude that b)the sample size is large enough to use the normal approximation.
176ft^2 first
141.3ft^2 second
Answer:
Whole numbers are all natural numbers including 0 e.g. 0, 1, 2, 3, 4… Integers include all whole numbers and their negative counterpart e.g. … -4, -3, -2, -1, 0,1, 2, 3, 4,… Where a and b are both integers.
Step-by-step explanation:
Answer:
Cone, Triangular Pyramid, and Square Pyramid
Step-by-step explanation:
The condition in the question says, two cross sections are the same in shape but are NOT congruent. Which means they might look alike but are not congruent.
If we consider two cross sections of a cylinder, they will be absolutely congruent since they share the same radius.
If we consider two cross sections of a triangular prism and rectangular prism they both have uniform dimension and the two cross sections will be congruent to each other.
But in the case of a cone, triangular pyramid, and square pyramid the cross sections might appear the same but they are not congruent since the dimension varies uniformly from one end to the other. For example, if we cut the cone at the top the radius of the base will not be the same if we cut it from some lower end, they will look the same but they will not be congruent.
Equation of circle is (x-h)²+(y-k)²=r²
- x²+y²-2x-8=0
- x²-2x-8+y²=0
- x²-2x+1-9+y²=0
- (x-1)²+y²-9=0
- (x-1)²+(y-0)²=9
- (x-1)²+(y-0)²=3²
Radius=3
Centre (1,0)
Option A and D are correct