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Strike441 [17]
3 years ago
10

What is the formula unit of zinc oxide

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
3 0
ZnO2. Zn is has +2 charge while Oxygen has a -1 charge, and in order to balance out the 2, you use 2 Oxygen atoms forming an oxide.
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A 2.144-g sample of phosgene, a compound used as a chemical warfare agent during World War I, contains 0.260 g of carbon, 0.347
Greeley [361]
First convert each mass to moles by dividing by the molar mass.

0.347g Oxygen = 0.022 moles
0.260g Carbon = 0.022 moles
1.537g Chlorine = 0.043 moles

Divide each by smallest mole vale (0.022)

Oxygen = 0.022/0.022 = 1
Carbon = 0.022/0.022 = 1
Chlorine = 0.043/0.022 = 2

Therefore the empirical formula is COCl2
4 0
3 years ago
What are the best note taking styles for high school?
photoshop1234 [79]

Answer:

cornell noted

Explanation:

used in middle school and can be helpful for subjects like ela history and science

5 0
3 years ago
Read 2 more answers
Calcium fluoride (CaF2) has a solubility constant of 3.45 x 10-11
tangare [24]
Ksp=3.45×10⁻¹¹

CaF₂(s) ⇄ Ca²⁺(aq) + 2F⁻(aq)

Ksp=[Ca²⁺][F⁻]²

[Ca²⁺]=C(CaF₂)
[F⁻]=2C(CaF₂)

Ksp=4{C(CaF₂)}³

C(CaF₂)=∛(Ksp/4)

C(CaF₂)=∛(3.45×10⁻¹¹/4)=2.05×10⁻⁴ mol/L

2.05×10⁻⁴ M
3 0
3 years ago
Write a balanced chemical equation for the reaction of copper(II) sulfate and concentrated ammonia to produce teramine copper(II
Rudiy27

Answer:

CuSO4(aq) + 4NH3(aq) + nH2O→ [Cu(NH3)4H2On]S04(aq)

Explanation:

When the concentrated ammonia is added into the copper ions solution, a blue solid is formed. This blue solid is gelatinous.it consist of Cu(OH)2 in insoluble form. As more ammonia is added precipitate start to dissolve and [Cu(NH3)4]∧+2 is produce.

Net Ionic equation:

Cu∧+2 +4NH3 →  [Cu(NH3)4]∧+2

S04∧-2 are spectator ions.

Properties and uses of Tetraaminecopper(ll) sulfate:

1. It is solid compound.

2. Its color is dark blue.

3. It has ammonia like odor.

4. It is used to make the copper compounds and also used in the printing of fabric.

5. It is also used as pesticide.

3 0
3 years ago
Given that H2 (g) + F2 (g) ⟶ 2HF (g) ΔH ∘ rxn = − 546.6 kJ 2H2 (g) + O2 (g) ⟶ 2H2O (l) ΔH∘rxn = − 571.6 kJ calculate the value o
BARSIC [14]

Answer : The value of \Delta H_{rxn} for the reaction is, -521.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

2F_2(g)+2H_2O(l)\rightarrow 4HF(g)+O_2(g)    \Delta H_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) H_2(g)+F_2(g)\rightarrow 2HF(g)     \Delta H_1=-546.6kJ

(2) 2H_2(g)+O_2(g)\rightarrow 2H_2O(l)    \Delta H_2=-571.6kJ

Now we are multiplying reaction 1 by 2 and reversing reaction 2 and then adding all the equations, we get :

(1) 2H_2(g)+2F_2(g)\rightarrow 4HF(g)     \Delta H_1=2\times (-546.6kJ)=-1093.2kJ

(2) 2H_2O(l)\rightarrow 2H_2(g)+O_2(g)    \Delta H_2=571.6kJ

The expression for enthalpy of change will be,

\Delta H=\Delta H_1+\Delta H_2

\Delta H=(-1093.2kJ)+(571.6kJ)

\Delta H=-521.6kJ

Thus, the value of \Delta H_{rxn} for the reaction is, -521.6 kJ

8 0
3 years ago
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