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SCORPION-xisa [38]
3 years ago
9

Calcium fluoride (CaF2) has a solubility constant of 3.45 x 10-11

Chemistry
1 answer:
tangare [24]3 years ago
3 0
Ksp=3.45×10⁻¹¹

CaF₂(s) ⇄ Ca²⁺(aq) + 2F⁻(aq)

Ksp=[Ca²⁺][F⁻]²

[Ca²⁺]=C(CaF₂)
[F⁻]=2C(CaF₂)

Ksp=4{C(CaF₂)}³

C(CaF₂)=∛(Ksp/4)

C(CaF₂)=∛(3.45×10⁻¹¹/4)=2.05×10⁻⁴ mol/L

2.05×10⁻⁴ M
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Lithium (Li): 1s 2sB<br> A=<br> B=
topjm [15]

Answer:

A = 2

B = 1

Explanation:

The atomic number of lithium is 3.

Its atomic mass is 7 amu.

It is present in group group 1.

It has one valance electron.

Lithium is alkali metal it form salts.

It is silvery soft metal. It has lowest density as compared to all other metals.

It react vigorously with water.

It is used in rechargeable batteries which are used in camera, mobile, laptops etc.

The electronic configuration of Li:

Li₃ = 1s² 2s¹

Thus,

A = 2

B = 1

8 0
2 years ago
Convert 45.2 g to lbs
dangina [55]

Answer:

0.09964894 pounds

Explanation:

3 0
3 years ago
Calculate the number of moles in 24.18 liters of neon gas at STP.
uranmaximum [27]

The number of moles of Neon gas : 1.079

<h3>Further explanation</h3>

Given

24.18 Liters of Neon gas at STP

Required

The number of moles

Solution

There are 2 conditions that are usually used as a reference in chemical calculations (mainly for determining the volume per mole of a gas or the molar volume), STP and RTP

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So mol for 24.18 L :

= 24.18 : 22.4

= 1.079 moles

8 0
3 years ago
By definition 12 grams of carbon-12 must contain how many atoms?
krek1111 [17]
It is defined as the amount of a substance that contains as many particles as there are atoms in 12 grams of pure carbon-12. So, 1 molecule contains 6.022×10^23 elementary entities of the substance.

Hope that helps
5 0
3 years ago
What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?
mr Goodwill [35]

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we <u>convert 166.00 g of KI into moles</u>, using its <em>molar mass</em>:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

  • 166.00 g ÷ 166 g/mol = 1 mol KI

Then we <u>calculate the required volume</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters

Liters = moles / molarity

  • 1 mol / 1.00 M = 1 L
3 0
2 years ago
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