Actual Resources: are those which have been surveyed, their quantity and quality determined and are being used in present times.
Potential Resources: <span>They can exist in a region and can be used in the future.</span>
Reduction is the gain of electrons, then potential of reducción is the tendency of a sustance to gain electrons. In this case the sustance is an electrode.
Then the reduction potential refers to the tendency of one electrode to gain electrons and it is measured against a standard electrode which is the electrode of hydorgen.
When you consider the pair of half-cell reactions, the potential of the cell is the reduction potential - oxidation potential.
Answer:
+523 kJ.
Explanation:
The following data will be used to calculate the average C-S bond energy in CS2(l).
S(s) ---> S(g)
ΔH = 223 kJ/mol
C(s) ---> C(g)
ΔH = 715 kJ/mol
Enthalpy of formation of CS2(l)
ΔH = 88 kJ/mol
CS2(l) ---> CS2(g)
ΔH = 27 kJ/mol
CS2(g) --> C(g) + 2S(g)
So we must construct it stepwise.
1: C(s) ---> C(g) ΔH = 715 kJ
2: 2S(s) ---> 2S(g) ΔH = 446 kJ
adding 1 + 2 = 3
ΔH = 715 + 446
= 1161 kJ
3: C(s) + 2S(s) --> C(g) + 2S(g) ΔH = 1161 kJ
4: C(s) + 2S(s) --> CS2(l) ΔH = 88 kJ
adding (reversed 3) from 4 = 5
ΔH = -1161 + 88
= -1073 kJ
5: C(g) + 2S(g) --> CS2(l) ΔH = -1073 kJ
6: CS2(l) ---> CS2(g) ΔH = 27 kJ
adding 5 + 6 = 7
ΔH = -1073 + 27
= -1046 kJ
7. C(g) + 2S(g) --> CS2(g) ΔH = -1046 kJ
Reverse and divide by 2 for C-S bond enthalpy
= -(-1046)/2
= +523 kJ.
A...because both of them(carbon and oxygen)are nonmetal
Answer:
NH3
Explanation:
there is one nitrogen and 3 hydrogen
