Answer:
Step-by-step explanation:
When a quadrilateral is inscribed in a circle, the opposite angles of it add up to 180 degrees.
Here,
∠DCB + ∠DAB = 180 (Opposite angles of a quad inscribed in a circle.)
<u>Given that:</u> ∠DCB = 135° and ∠DAB = x
135 + x = 180
Subtract 135 to both sides
x = 180 - 135
x = 55°
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
<u>Answer</u>
0
<u>Explanation</u>
(2m)/(2m+3)-(2m)/(2m-3)=1
Simplifying the left hand first
(2m)/(2m+3)-(2m)/(2m-3) = {2m(2m-3) - 2m(2m+3)}/(4m²-9)
(4m²-6m-4m²-6m)/(4m²-9)
= (-12m) / (4m²-9)
Now this equet to 1
(-12m) / (4m²-9) = 1
-12m = 4m²-9
4m²+ 12m -9 =0 ⇒⇒⇒ This is a quadratic equation that has 2 real solutions.
4m²+ 12m -9 =0
m² + 3m + (3/2)²= 9/4 + 9/4
(m + 3/2)² = 18/4
m = √18/2 - 3/2 or m = -√18/2 - 3/2
= 0.621 = -3.621
So we can say that the equation has NO extraneous solutions.
Answer = 0
Answer:
Can you please organize this text.
Answer:it’s a I think
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
The people arent random
