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3 years ago

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The drama club is showing a video of their recent play. The first showing begins at 2:30 p.m. The second showing is scheduled at

5:25 p.m. with a 1/2 hour break between the showings. How long is the video in hours and minutes?

1 answer:

snow_tiger [21]3 years ago

3 0

Your answer would be 2 hours and 25 minutes

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C) 15 X (-25) * (-4) X (-10 )<br><br>please say 100 points

natta225 [31]

Answer:

15 × (-25) × (-4) × (-10)

= 15 × 100 × 10

= 15000

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3 years ago

ILL GIVE YOY BRAINLIST *have to get it right * What is the slope of the line shown in the graph?

xz_007 [3.2K]

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Step-by-step explanation:

3 over 2 down.

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3 years ago

sarah uses a recipe to make 2 gallons of her favorite mixed-berry juice. the containers she plans to use to store the juice have

BabaBlast [244]

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3 years ago

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xxTIMURxx [149]

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Step-by-step explanation:

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3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

3 years ago