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anygoal [31]
3 years ago
12

The drama club is showing a video of their recent play. The first showing begins at 2:30 p.m. The second showing is scheduled at

5:25 p.m. with a 1/2 hour break between the showings. How long is the video in hours and minutes?
Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0
Your answer would be 2 hours and 25 minutes
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Henrietta did an experiment. She started out with 700 bacteria cells. She found that the growth rate of the bacteria cells was 5
poizon [28]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have a exponential function of the form

y=a(b^x)

where

y ---> is the population of bacteria

x ---> the number of hours

a is the initial value or y-intercept

b is the base of the exponential function

r is the rate of change

b=(1+r)

we have

a=700\ bacteria

r=5\%=5/100=0.05

so

b=1+0.05=1.05

substitute

y=700(1.05^x)

For x=20 hours

substitute in the equation and solve for y

y=700(1.05)^{20} =1,857\ bacteria

4 0
3 years ago
27 vector mechanics for engineers volume 11 answer
astra-53 [7]
I think its missing info?
4 0
3 years ago
Investigate the range of each parent function below over the interval o ranges from least to greatest.<br> Identity function, re
Y_Kistochka [10]

Answer:

Here we have the domain:

D = 0 < x < 1

And we want to find the range in that domain for:

1) y = f(x) = x

First, if the function is only increasing in the domain (like in this case) the minimum value in the range will match with the minimum in the domain (and the same for the maximums)

f(0) = 0 is the minimum in the range.

f(1) = 1 is the maximum in the range.

The range is:

0 < y < 1.

2) y = f(x) = 1/x.

In this case the function is strictly decreasing in the domain, then the minimum in the domain coincides with the maximum in the range, and the maximum in the domain coincides with the minimum in the range.

f(0) = 1/0 ---> ∞

f(1) = 1/1

Then the range is:

1 < x.

Notice that we do not have an upper bound.

3) y = f(x) = x^2

This function is strictly increasing, then:

f(0) = 0^2 = 0

f(1) = 1^2 = 1

the range is:

0 < y < 1

4) y = f(x) = x^3

This function is strictly increasing in the interval, then:

f(0) = 0^3 = 0

f(1) = 1^3 = 1

the range is:

0 < y < 1.

5) y = f(x) = √x

This function is well defined in the positive reals, and is strictly increasing in our domain, then:

f(0) = √0 = 0

f(1) = √1 =1

The range is:

0 < y < 1

4 0
3 years ago
What’s the value of DCB?<br> Pls help
amm1812

Answer:

78

Step-by-step explanation:

angle ACD + angle DCB = 180   (Angles on straight line)

4x + 2 + 3x + 3 = 180

7x + 5 = 180

7x = 180-5

7x = 175

x = 175 / 7

x = 25

angle DCB = 3x +3 = 3*25 + 3 = 75 +3 = 78

6 0
2 years ago
2m - 6 = 8m then 3m =
Vinil7 [7]

Answer:

3m = -3

Step-by-step explanation:

You are given

2m - 6 = 8m,

hence,

2m - 8m = 6,

-6m = 6,

m = 6%2F%28-6%29,

m = -1.

Therefore, 3m = -3.

5 0
3 years ago
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