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fredd [130]
3 years ago
10

Helpppppppp please helppppp I’ll give Brainliest

Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Answer: B

Step-by-step explanation:

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Can you use the SSS Postulate or the SAS Postulate to prove triangle FEZ is congruent to triangle FGZ?
love history [14]
SAS only. The 3rd side cannot be proven. 
8 0
3 years ago
The hypotenuse and one of the legs of a right triangle form an angle that has a cosine of 2 √2 .
Tems11 [23]
Quick answer I don't think this has an answer.

If you take the cos-1(2 sqrt(2)) your calculator should have a fit. Let's check that out. Mine certainly does. So there is something wrong with the question. If there is something to add in please do it and I will it least put an answer in the comments. As it stands, nothing will work. 

If you put your calculator in radians, you will get an answer but it will not be anything resembling the choices you've listed.

If you meant sqrt(2) / 2 that would give 45o. Put it in your calculator like this 2 ^ 0.5 divided by 2 = 0.707
Cos - 1 (0.707) = 45



7 0
3 years ago
Read 2 more answers
Finish labeling the number of elements in the regions in the Venn diagram shown to the right, where the subsets
Virty [35]

Answer:

t=14

v=13

q=12

s=23

w=-4

x=28

Step-by-step explanation:

we know that the universal set =100

so, everything in it must add up to 100

first, from the information given to us,

t= n(A n C)= 14

v=n(B n C)= 13

to find q

we know from our guide that n(A) =40

which means everything inside A will add up to 40

therefore,

q + 7 + 7 + t = 40

and we already know that t = 14

so, that will be;

q + 7 + 7 + 14 = 40

therefore, q = 12

to find s,

we all know that n(B) = 50

which means that everything inside B will be equal to 50

therefore,

s + 7 + 7 + v = 50

and we know that v = 13

therefore,

s + 7 + 7 + 13 = 50

and s will end up to be = 23

to find w,

we know that n(C) = 30

so, everything in C end up to be all equal to 30

therefore,

t + 7 + w + v = 30

from our solution, t = 14, v = 13

so,

14 + 7 + w

4 0
3 years ago
The number of students in an school building that have the flu after t days is given by the function
gulaghasi [49]

Step-by-step explanation:

p(0) =  \frac{800}{1 + 49 {e}^{ - 0.2 \times 0} }  =  \frac{800}{1 + 49}  =  \frac{800}{50}  = 16

200 =  \frac{800}{1 + 49 {e}^{ - 0.2t} }  \\ 200(1 + 49 {e}^{ - 0.2t} ) = 800 \\ 200 + 9800 {e}^{ - 0.2t}  = 800 \\ 9800 {e}^{ - 0.2t}  = 600 \\  {e}^{ - 0.2t}  =  \frac{3}{49}  \\  ln( {e}^{ - 0.2t} )  =  ln( \frac{3}{49} )  \\ -  0.2t =  - 2.793 \\ t = 13.96 = 14

6 0
3 years ago
If $1,000 is invested at 4% simple interest, how much will the investment be worth after 2 years? Please explain how compound an
Novay_Z [31]
<h3>Answer:</h3>
  • simple interest: $1080.00
  • compounded annually: $1081.60
<h3>Step-by-step explanation:</h3>

<em>Simple Interest</em>

Simple interest is computed on the principal amount only. Each year, 4% of the principal is added to the balance. So, at the end of 2 years, the balance is ...

... $1000 + 0.04×$1000 + 0.04×$1000

... = $1000×(1 + 0.04×2) = $1000×1.08

... = $1080.00

_____

<em>Comment on the computation</em>

The added interest is the rate (per year) multiplied by the number of years. Here, that is 0.04×2×(principal amount). The formula for the simple interest earned is often seen as ...

... I = Prt . . . . . where I is the amount of interest, P is the principal amount, r is the interest rate for the time period, t is the number of time periods.

The account balance (A) with interest added is ...

... A = P + I = P + Prt

... A = P(1 +rt)

Here, the time period is years, and the rate given is an annual rate.

____

<em>Compound Interest</em>

Compound interest is computed on the <em>account balance</em> at the beginning of the period, not just the <em>principal</em> amount. After the first period, the account balance includes interest earned so far. So, the interest is earning interest. That is why it is called compounded interest.

Here, the balance at the end of the first year is the principal amount plus the interest that has earned:

... $1000 + 0.04×$1000 = $1000×1.04 = $1040.00

The balance at the end of the second year when the interest is compounded is this account balance plus the interest it earns:

... $1040 + 0.04×$1040 = $1040×1.04 = $1081.60

You may notice that the intial principal, $1000, has been multiplied by the factor 1.04 twice. Using exponents, the multiplier for a period of 2 years is 1.04×1.04 = 1.04².

_____

<em>Comment on the computation</em>

The multiplier of the account balance each year is raised to a power that is the number of years. Here, the account balance at the end of 2 years is (1+0.04)² times the principal amount. A formula that is seen for this is ...

... A = P(1 +r)^t . . . . . where A is the final account balance, P is the principal amount, r is the interest rate for the time period, and t is the number of time periods.

7 0
3 years ago
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