H(x)=2x+5/3

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0

3 years ago

How many vertices does a heptagon have

Olegator [25]

Hey! There are 7 sides and 7 vertices on a Heptagon. Hope this helps!

5 0

3 years ago

Read 2 more answers

DESPERATE WILL GIVE BRAINLIST AND THANKS

Anna35 [415]

Answer:

1345

Step-by-step explanation:

5 0

3 years ago

Find the missing values on the diagram below. Assume that each line is evenly divided. I'm pretty confused on the right side of

belka [17]

Answer:

A = 72 B = 50% C = 40%

Step-by-step explanation:

Each space on the bottom is worth 10%.

Each space on the bottom is worth 36.

7 0

3 years ago

F $1 \le a \le 10$ and $1 \le b \le 36$, for how many ordered pairs of integers $(a, b)$ is $\sqrt{a + \sqrt{b}}$ an integer?

svetlana [45]

You have such entry data:
$1\ \textless \ a\ \textless \ 10 \\ 1\ \textless \ b\ \textless \ 36$

Consider expression $\sqrt{a+ \sqrt{b} }$ . If this expression becomes an integer, then b=4,9,16,25, because then $\sqrt{b} =$ 2,3,4,5, respectively. In other cases $\sqrt{b}$ is not integer and thus the expression $\sqrt{a+ \sqrt{b} }$ also is not integer.

1. b=4, then $\sqrt{a+ \sqrt{b} }=\sqrt{a+2}$ . Here a=2,7 (in other cases $\sqrt{a+2}$ is not integer). When a=2, $\sqrt{a+2}=\sqrt{2+2}=2$ and when a=7, $\sqrt{a+2}=\sqrt{7+2}=3$ .

2. b=9, then a=6 and $\sqrt{a+ \sqrt{b} }= \sqrt{a+3}=\sqrt{6+3}=3$ .

3. b=16, then a=5 and $\sqrt{a+ \sqrt{b} }= \sqrt{a+4}=\sqrt{5+4}=3$ .

4. b=25, then a=4 and $\sqrt{a+ \sqrt{b} }=\sqrt{a+5}=\sqrt{4+5}=3$ .

Answer: (2,4), (7,4), (6,9), (5,16), (4,25).

3 0

3 years ago