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ratelena [41]
3 years ago
15

What is the standard form of this expression? (4y - 9/2y - 3)

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

-1/2y-3

Step-by-step explanation:

4y-9/2y-3

8/2y-9/2y-3

-1/2y-3

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Liam wants to save $6,265 to purchase a car. if $4,000 is deposited into an account at 7.5% interest, compounded monthly, how ma
timurjin [86]
To solve for time taken we use the compound formula:
A=P(1+r/100*n)^(n*t)
where:
A=future value
P=principle
r=rate
t=time
n=number of terms

6265=4000(1+7.5/(12*100))^(12t)
solving for t we get
1.56625=1.00625^12t
12t=72.0136
t=6.00 years
Answer: 6 years
5 0
3 years ago
A light bulb consumes 1440 watt hours per day. How many watt hours does it consume in 5 days and 18 hours
Maurinko [17]

Answer:

8,280 watt hours

Step-by-step explanation:

1440/24 = 60 watt hours per hour

5*24=120 hours in 5 days

120+18=138

138*60=8,280 watt hours

4 0
3 years ago
There are more than one answer help me and I give brainilest
andreev551 [17]

Answer:

Equivalent to a), b), and d). It is NOT equivalent to c).

Step-by-step explanation:

6m + 12 is also equivalent to a) 3(2m+4) because when you distribute, it's 6m + 12. It is also equivalent to b) 3m + 8 + 4 + 3m because if you add them together, you get 6m + 12. It is not equivalent to c) but is do d) 4m + 2(m + 6) cause you use the distributive property then add. I hope this helped and please mark brainliest!

4 0
3 years ago
9 times the quantity of 12 less than a number x is 24. Write in an algebraic expression.
kiruha [24]

Answer:

9(x-12)=24

Step-by-step explanation:

5 0
2 years ago
Help pleaseeeeeeeeeeeeeeeeeeeeeee
bixtya [17]

Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

3 0
3 years ago
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