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3 years ago

I need help to find the expanded form of 39,012

Mathematics

2 answers:

lions [1.4K]3 years ago

4 0

39,012 in expanded form is 30,000+9,000+0+10+2

Tema [17]3 years ago

3 0

we know that

Expanded form is a way to write a number by adding the value of its digits

$39,012$ in expanded form is equal to

$39,012=3*10,000+9*1,000+0*100+1*10+2*1\\ 39,012=30,000+9,000+10+2$

therefore

the answer is

$39,012=30,000+9,000+10+2$

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Solve the equation.<br><br>-4 (y - 2) = 12<br><br>y = ?

inna [77]

First you distribute what’s outside the parentheses (the -4)

-4•4= -4y
-4•-2= 8

New equation: -4y+8=12

Now you solve like a normal equation
12-8 is 4

New equation: -4y=4

Now divide

Answer:-1

8 0

3 years ago

There are about 10^24 stars in the universe. Each galaxy has approximately the same number of stars as the Milky Way Galaxy. Abo

maks197457 [2]

Answer:

$10^{13}$ galaxies.

Step-by-step explanation:

There are about $10^{24}$ stars in the universe.

The Milky Way galaxy $10 * 10^{10}$ stars.

All we need to do to find the number of galaxies is to divide the total number of stars in the universe by the number of stars in the Milky Way:

Number of galaxies = (Number of stars in the universe) / (Number of stars in the Milky Way)

Number of galaxies = $\frac{10^{24}}{10 * 10^{10}}$

N = $\frac{10^{24}}{10^{11}}$

N = $10^{24 - 11} = 10^{13}$

The number of galaxies in the universe is approximately $10^{13}$ .

7 0

3 years ago

You go shopping at a local department store with your friend and cousin. You buy one pair of jeans, four pairs of shorts, and tw

VashaNatasha [74]

Answer: Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

Step-by-step explanation:

Let x= cost per pair of jeans

y = Cost per pair of shorts

z= cost per shirt.

For you, total cost = x+4y+2z= 84

For your friend, total cost = 2x+y+3z=76

For cousin, total cost = x+2y+z= 52

Required system:

$x+4y+2z=84\ (i)\\ 2x+y+3z=76\ (ii)\\ x+2y+z=52\ (iii)$

from (i), $x=84-4y-2z$ (*)

put this in (ii) and (iii) we get

$2\left(84-4y-2z\right)+y+3z=76\\\Rightarrow\ -7y-z+168=76\ (iv)\\\\ 84-4y-2z+2y+z=52\\\Rightarrow\ -2y-z+84=52 \ (v)$

from (iv), $y=-\frac{z-92}{7}\ (vi)$

$\mathrm{Subsititute\:}y=-\frac{z-92}{7}\ \text{in}\ (v)$

$-2\left(-\frac{z-92}{7}\right)-z+84=52\\\\\Rightarrow\ -2\left(-\frac{z-92}{7}\right)-z=-32\\\\\Rightarrow\ -\frac{5z}{7}-\frac{184}{7}=-32\\\\\Rightarrow\ -5z-184=-224\\\\\Rightarrow\ -5z=-40\\\\\Rightarrow\ z=8$