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Nataly_w [17]
3 years ago
7

What is the positive solution to the equation 0 = –x2 + 2x + 1? Quadratic formula: x = StartFraction negative b plus or minus St

artRoot b squared minus 4 a c EndRoot Over 2 a EndFraction –2 + StartRoot 2 EndRoot 2 – StartRoot 2 EndRoot 1 + StartRoot 2 EndRoot –1 + StartRoot 2 EndRoot
Mathematics
2 answers:
romanna [79]3 years ago
9 0

Answer:

1+\sqrt{2}

Step-by-step explanation:

If a quadratic equation is defined as

ax^2+bx+c=0          .... (1)

then the quadratic formula is

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

The given quadratic equation is

0=-x^2+2x+1

It can we written as

-x^2+2x+1=0             .... (2)

On comparing (1) and (2) we get

a=-1,b=2,c=1

Substitute these values in the quadratic formula.

x=\dfrac{-2\pm \sqrt{2^2-4(-1)(1)}}{2(-1)}

x=\dfrac{-2\pm \sqrt{4+4}}{-2}

x=\dfrac{-2\pm \sqrt{8}}{-2}

x=\dfrac{-2\pm 2\sqrt{2}}{-2}

Taking out common factors.

x=\dfrac{-2(1\pm \sqrt{2})}{-2}

x=1\pm \sqrt{2}

Two roots are

x=1+\sqrt{2} and x=1-\sqrt{2}

We know that

\sqrt{2}=1.41

So

1

Therefore, root x=1+\sqrt{2} is positive and x=1-\sqrt{2} is negative.

murzikaleks [220]3 years ago
3 0

Answer:

C on edge

Step-by-step explanation:

Just took the test!

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Answer:

A. 162 m²

Step-by-step explanation:

==>Given:

Isosceles trapezoid with:

base a = 19m

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==>Required:

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==>Solution:

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= ½ × (19+35) × 6

= ½ × 54 × 6

= 27 × 6

Area = 162m²

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