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ValentinkaMS [17]
3 years ago
5

Paul's doctor says his cardiorespiratory fitness level is excellent, but she worries about Paul's muscular fitness. Paul enjoys

gymnastics, baseball, biking, and yoga. Increasing the frequency of which activity will best improve Paul's muscular fitness? (3 points)
Gymnastics
Baseball
Biking
Yoga
Chemistry
2 answers:
Lelu [443]3 years ago
4 0

Answer: Gymnastics

kiruha [24]3 years ago
3 0

Answer:

Explanation:

Gymnastics

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What is the correct interpretation of the mole ratios for the elements in
iogann1982 [59]

Answer:

the ratio would be 1:2:1

Explanation:

since it is C6 H12 O6

12 is double of 6 so it would be 2

and 6 is considered 1

6 0
3 years ago
Read 2 more answers
Write a balanced chemical equation for the combustion of C6H12O6 in oxyegen gas
Anestetic [448]

C6H12O6 (s) + 6O2 (g) + 6CO2 (g) + 6H2O(l)

3 0
3 years ago
An electron na hydrogen atom moves from level to level 4 The electron then drops from level 4 to level 2. Which statement
Vsevolod [243]

Answer:

The energy absorbed in the first move is greater than the energy released in the second move.

Explanation:

The greater the level number the greater the energy.

A movement up a level requires energy so energy id absorbed.

Dropping down a level releases energy.

3 0
3 years ago
What is the pressure in atm of 0.47mol of a gas in a 1.7L container at 276K?
polet [3.4K]
The answer is 1. A sample of 0.50 moles of gas is placed in a container of volume of 2.5 L. What is the pressure of the gas in torr if the gas is at 25oC? P = 4.89 atm = 3719 torr

2. A sample of gas is placed in a container at 25oC and 2 atm of pressure. If the temperature is raised to 50oC, what is the new pressure? P = 2.17 atm

3. At 1 atm of pressure water boils at 100oC, if the sample was placed under 2 atm of pressure, what would be the temperature? (This would be like a pressure cooker).
T = 746 K = 473oC = 883oF

4. At what temperature would water boil if the pressure is 600 torr? (Use information from problem 3: this shows why food doesn't cook well at higher elevations)
T = 294 K = 21.5oC = 70.7oF

5. Calculate the volume of 40.6 g of F2 at STP. V = 23.9 L

6. A sample of 2.0 moles of hydrogen gas is placed in a container with a volume of 10.4 L. What is the pressure of the gas in torr if the gas is at 25oC? P = 4.70 atm = 3576

7. The tire pressure is 32 psi. What is the pressure in torr if 1 atm = 14.7 psi?
P = 1654 torr

8. A gas is placed in a balloon with a volume of 3.0 L at 28oC and 900 torr. What would be the new volume for the gas if placed under STP? V = 3.2 L

9. How many moles of gas would occupy a volume of 14 L at a pressure of 700 torr and a temperature of 30oC? n = 0.52 mol

10. Calculate the volume of 24.0 g of HCl at STP. V = 14.8 L

11. What is the volume of one mole of acetylene gas at STP? V =22.414 L

12. What is the volume of 0.75 mol of gas at 72oC and 2 atm? V = 10.6 L

13. After eating beans, a student collects a sample of gas at 0.97 atm and 26oC which occupies a volume of 3.5 L, calculate its volume at STP. V = 3.1 L

14. Ammonia (NH3) is placed in 1.5 L flask at 25oC. If the pressure of the gas is 0.899 atm, what is the density? d = 0.626 g/L

15. A mixture of Ar and CO gases is collected over water at 28oC and an atmospheric pressure of 1.05 atm. If the partial pressure of Ar is 600 torr, what is the partial pressure of CO? (vapor pressure of water at 28oC is 28.3 mmHg) PCO = 0.223 atm

16. Determine the partial pressures of each of the gases in the following mixture: 17.04 g NH3, 40.36 g Ne and 19.00 g F2. The gases are at 1.5 atm of pressure.
PNH3 = 0.428 atm; PNe = 0.857 atm; PF2 = 0.2124 atm

17. Potassium chlorate decomposes under heat as follows:

2 KClO3 (s) -------> 2 KCl (s) + 3 O2 (g)

The oxygen gas is collected over water at 25oC. The volume of gas is 560 mL measured at 1 atm. Calculate the number of grams of KClO3 used in the reaction. (vapor pressure of water = 0.0313 atm) nO2 = 0.022 mol; 1.81 g KClO3
5 0
2 years ago
Choose the reaction that represents the combustion of C6H12O2.
Leona [35]

Answer:

The answer to your question is:  letter D

Explanation:

In a combustion reaction, the reactants are always a molecule with Carbon that reacts with oxygen and the products are carbon dioxide and water.

According to the explanation, the only possible solution is:

a) C₆H₁₂O₂(l) ⇒ 6 C(s) + 6 H₂(g) + O₂(g)

b) Mg(s) + C₆H₁₂O₂(l) ⇒ MgC₆H₁₂O₂(aq)

c) 6 C(s) + 6 H₂(g) + O₂(g) ⇒ C₆H₁₂O₂(l)

d) C₆H₁₂O₂(l) + 8 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(g)

e) None of the above represent the combustion of C₆H₁₂O₂.

4 0
3 years ago
Read 2 more answers
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