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ValentinkaMS [17]
3 years ago
5

Paul's doctor says his cardiorespiratory fitness level is excellent, but she worries about Paul's muscular fitness. Paul enjoys

gymnastics, baseball, biking, and yoga. Increasing the frequency of which activity will best improve Paul's muscular fitness? (3 points)
Gymnastics
Baseball
Biking
Yoga
Chemistry
2 answers:
Lelu [443]3 years ago
4 0

Answer: Gymnastics

kiruha [24]3 years ago
3 0

Answer:

Explanation:

Gymnastics

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Calculate freeze 62.9 g of iron at 1535oC<br> Hf (J/g)=257
Inessa [10]

Answer:

<u>-16200J</u>

Explanation:

(257J/g)(62.9g)

eliminate the variables

u get 16165.3

go to 3 significant digits

u get 16200

and since it is freezing we are taking out energy so it would be

-16200J

4 0
4 years ago
Which element combinations do not form compounds?
Degger [83]
Chlorine and hydrogen
3 0
3 years ago
Read 2 more answers
Atoms of elements in the same group have the same number of . This is why they have similar chemical properties.
Dennis_Churaev [7]

Answer:

Same number of electrons in their outer shell.

Explanation:

Whe working out their electronic configuration ( by looking at the atomic number) , one will find out that the number of electrons in their outer shell is also the same so the elements have to lose or gain the same amount of electrons to become stable.

4 0
3 years ago
Read 2 more answers
Which of the following compounds are ionic?
julsineya [31]

Answer:

a. KCl, c. BaCl2 and e. LiF.

Explanation:

Hello,

In this case, we can identify the ionic compounds by verifying the difference in the electronegativity between the bonding compounds when it is 1.7 or more (otherwise it is covalent) as shown below:

a. KCl: 3.0-0.9=2.1 -> Ionic.

b. C2H4: 2.5-2.1=0.4 -> Covalent.

c. BaCl2: 3.0-0.8=2.2 -> Ionic.

d. SiCl4: 3.0-1.8=1.2 -> Covalent.

e. LiF: 4.0-1.0=3.0 -> Ionic.

Therefore, ionic compounds are a. KCl, c. BaCl2 and e. LiF.

Regards.

7 0
3 years ago
What is the wavelength of radiation that has a frequency of 7.2×10^11 s−1 ?
Airida [17]

Explanation:

It is known that relation between wavelength and frequency is as follows.

                  \lambda = \frac{c}{\nu}

where,        \lambda = wavelength

                       c = speed of light = 3 \times 10^{8} m/s

                  [/tex]\nu[/tex] = frequency

It is given that frequency is 7.2 \times 10^{11} s^{-1}. Hence, putting this value into the above formula and calculate the wavelength as follows.

                    \lambda = \frac{c}{\nu}

                    \lambda = \frac{3 \times 10^{8} m/s}{7.2 \times 10^{11} s^{-1}}

                             = 0.416 \times 10^{-3} m

or,                         = 4.16 \times 10^{-4} m

Thus, we can conclude that wavelength of given radiation is 4.16 \times 10^{-4} m.

6 0
3 years ago
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