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2 years ago

10

Drag and drop the labels provided into the boxes below to explain how the Earth-Sun-Moon system results in these seasons on Eart

h.

1 answer:

GalinKa [24]2 years ago

6 0

In order: tilted, rotates, revolving.

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How many moles of hydrogen are required to react with 4.6 x 10 22 molecules of nitrogen?

V125BC [204]

Answer: 6 moles

Take a look at the balanced chemical equation for this synthesis reaction

N 2(g] + 3 H 2(g] → 2 NH 3(g]

Notice that you have a 1:3 mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have 2 moles of nitrogen taking part in the reaction, you will need

2 moles N 2 ⋅ 3 moles H 2 /1 mole N 2 = 6 moles H 2

8 0

3 years ago

Zachary adds 9.7 g to 1.114 g.<br> How many significant figures should his answer have?

makvit [3.9K]

Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs

5 0

3 years ago

Which of the following is the best definition of a scientific theory?Help me plz

tatiyna

A scientific theory is a well tested explanation of a natural phenomenon.

7 0

3 years ago

At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?

Oksi-84 [34.3K]

image? cant do it without it

5 0

3 years ago

Precision Problems:

Lorico [155]

Answer:

$Precision = 2.70 \± 0.1\ cm$

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

$Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm$

$Mean = \frac{18.9}{7}\ cm$

$Mean = 2.70\ cm$

Step 2: Get The Range

$Range = Highest - Lowest$

$Range = 2.80cm - 2.60cm$

$Range = 0.2\ cm$

Step 3: Divide Range by 2

$Approximate\ Range = \frac{1}{2}Range$

$Approximate\ Range = \frac{1}{2} * 0.2\ cm$

$Approximate\ Range = 0.1\ cm$

Step 4: Determine the Precision

$Precision = Average \± Approximate\ Range$

Substitute 2.70 for Average and 0.1 for Approximate Range

$Precision = 2.70 \± 0.1\ cm$

4 0

3 years ago