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Anna71 [15]
2 years ago
12

What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 128 g of HCl

and aqueous phosphorous acid (H₃PO₃)?
Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
8 0

Water, H2O, and liquid phosphorus trichloride, PCl3, react quickly and exothermically. The reaction then produces aqueous hydrochloric acid (HCl) and aqueous phosphorous acid (H3PO3(aq)) (aq). Following is the balanced chemical reaction: PCl3 + 3 H2O H3PO3 + 3 HCl. Phosphorous acid, one of its byproducts, is a crucial precursor in the production of other phosphorous compounds.

<h3 /><h3>What is Phosphorous acid?</h3>

The substance denoted by the formula H3PO3 is phosphoric acid, often known as phosphonic acid (singular). Instead of being triprotic as this formula might imply, this acid is diprotic (easily ionizes two protons). An intermediary in the creation of other phosphorus compounds is phosphoric acid. Phosphonic acids are organic molecules having the formula RPO3H2 that are phosphorous acid derivatives.

To learn more about Phosphorous acid from the given link:

brainly.com/question/3700851

#SPJ4

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Two 0.75 Amp loads are connected in parallel with a 2500 Milliamperehour Ni-Cd battery. Approximately how long can the battery p
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Explanation:

It is given that two loads have 0.75 Ampere current each. And, they contain 2500 milli ampere per hour Ni-Cd battery.

As both the loads are connected in parallel. Hence, total current will be calculated as follows.

               I = I_{1} + I_{2}

                 = 0.75 A + 0.75 A

                 = 1.5 A

                 = 1.5 A \times \frac{1000 mA}{1 A}

                 = 1500 mA

Relation between time and capacity of battery is as follows.

             Capacity = Current × time (in hour)

therefore,        time = \frac{Capacity}{Current}

                                = \frac{2500 mA. h}{1500 A}

                                = 1.667 hr

Thus, we can conclude that the battery provide power to the load up to 1.667 hours.

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4 years ago
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3 years ago
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Answer: A

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A 3.42 gram sample of an unknown gas is found to occupy a volume of 1.90 L at a pressure of 547 mm Hg and a temperature of 33 °C
liq [111]
Use the Ideal Gas Law to find the moles of gas first.

Be sure to convert T from Celsius to Kelvin by adding 273.

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PV = nRT —> n = PV/RT
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V = 1.90 L
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R = 0.08206 L atm / mol K

n = (0.720 atm)(1.90 L) / (0.08206 L atm / mol K)(306 K) = 0.0545 mol of gas

Now divide grams by mol to get the molecular weight.

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