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Masteriza [31]
3 years ago
9

in times of hot dry weather some cities ban the use of garden sprinklers why do you think there is such a rule

Chemistry
2 answers:
Over [174]3 years ago
8 0

Answer:

To restrict the amount of water being utilized from a limited supply.

Explanation:

A sprinkler or a hosepipe ban gets imposed in certain cities during hot weather conditions in order to conserve the declining levels of drinking water, that is, stored in the reservoirs at the time of drought. Once the rainy season comes back the ban gets lifted as the reservoirs get filled once again, and it is more essential to provide water to the public, as the grass can always grow again.

Solnce55 [7]3 years ago
7 0

ban the use of garden sprinklers during hot dry weather because If water use doesn't decrease soon, pressure could start dropping and supplies could cut out without warning. Weeks of dry weather, high temperatures and warm winds have pushed water use almost to the limit.


 

                                                                                                                                      

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Which of the following statements is not true regarding physical properties and changes?
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How many grams of NaOH are needed to make 0.250 liter of a 0.500 M solution of NaOH? 0.125 g 5.00 g 2.00 g
makkiz [27]

Answer:

5.00g

Explanation:

Molarity is moles per liter

Therefore:

x moles/.250L = .5 moles/1L

Solve for x: .125 moles required

Question asks for grams of NaOH so multiply the moles by the molar mass of NaOH

.125(39.997) = 4.999625g

Rounds to 5.00g

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3 years ago
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The air inside a flexible 3.5L container has a pressure of 115Kpa. What should the volume of the container be increased to in th
LenaWriter [7]

Answer:

V₂ = 4.82 L

Explanation:

Given data:

Initial volume of gas = 3.5 L

Initial pressure = 115 Kpa

Final volume = ?

Final Pressure = 625 torr

Solution:

Final Pressure = 625 torr (625/760 =0.82 atm)

Initial pressure = 115 Kpa (115/101 = 1.13 atm)

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.13 atm × 3.5 L = 0.82 atm × V₂

V₂ = 3.955 atm. L/0.82 atm

V₂ = 4.82 L

5 0
4 years ago
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KengaRu [80]
The answer is the convergent boundary hope this helps
8 0
4 years ago
⦁answer Calculate the density in g/L of 478 mL of krypton at 47° C and 671 mm Hg. ⦁ Determine the molar mass of a gas that has a
STALIN [3.7K]

Answer:

The correct answers are:

- Krypton: density= 2.8 g/L

- Molar Mass= 63.99 g/mol

- Mass of O₂= 15.29 g

Explanation:

The general equation of an ideal gas is the folllowing:

P x V = n x R x T

Where: P= pressure (in atm), V= volume; n= number of moles, R= gas constant (0,082 L.atm/K.mol) and T= temperature (in K).

<u>For krypton</u>:

P= 671 mmHg = 0,882 atm

V= 478 ml x 1000 ml/1 L= 0,478 L

T= 47ºC= 320 K

MM= 83.8 g/mol (from Periodic Table, Kr is an inert gas so it is a monoatomic gas)

P x V = n x R x T

Since the number of moles of a compound can be calculated by dividing the mass of compound (m) into its molar mass (MM):

n= m/MM

We can replace the expression in the first equation to obtain:

P x V= \frac{m}{MM} x R x T

m/V= \frac{P x MM}{R x T}

Density (d) is equal to the mass per volume (m/V), so we can directly calculate the density:

d= m/V= \frac{P x MM}{R x T}=

           = (0.882 atm x 83.8 g/mol)/(0.082 L.atm/K.mol x 320 K)

           = 2.81 g/L

<u>For the gas:</u>

d= 2.18 g/L

T= 66ºC= 339 K

P= 720 mmHg= 0.947 atm

d= \frac{P x MM}{R x T}

⇒MM = \frac{dx R x T}{P}

         = (2.18 g/L x 0.082 L.atm/K.mol x 339 K)/(0.947 atm)

         = 63.99 g/mol ≅ 64 g/mol

<u>For the O₂</u>:

V= 5.60 L

P= 1.75 atm

T= 250 K

MM(O₂) = 2 x Atomic Mass O= 2 x 16 g/mol= 32 g/mol

We can use the second equation:

P x V= \frac{m}{MM} x R x T

⇒  m = \frac{P x V x MM}{R x T}= (1.75 atm x 5.6 L x 32 g/mol)/(0.082 L.atm/K.mol x 250 K)

                         = 15.29 g≅ 16 g

4 0
3 years ago
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