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lana66690 [7]
2 years ago
7

- The subatomic particle possessing the largest

Chemistry
1 answer:
Ierofanga [76]2 years ago
6 0

Answer:

B. electrons possess the largest charge-to-mass ratio among the subatomic particles listed in the four choices.

Explanation:

Consider the mass of each particle. Express the masses in atomic mass units:

  • Protons: approximately 1.007 amu each;
  • Neutrons: approximately 1.009 amu each;
  • Electrons: approximately 0.0005 amu each.

Similarly, consider the charge on each particle. Express the charges in multiples of the fundamental charge:

  • Protons: +1 e;
  • Neutrons: 0;
  • Electrons: -1 e.

Calculate the charge-to-mass ratio for the three species:

  • Protons: approximately \rm 0.99\; e\cdot amu^{-1};
  • Neutrons: 0;
  • Electrons: approximately \rm 1,800\;e \cdot amu^{-1}.

Almost all nuclei contain protons and neutrons. The only exception is the hydrogen-1 nucleus, which contains only one proton and no neutron. The mass of the nucleus is approximately the same as the sum of its components' masses. The extra neutron will only add to the mass of the nucleus (the denominator) without contributing to the charge (the numerator.) As a result, the charge-to-mass ratio of nuclei will be positive but no greater than the charge-to-mass ratio of protons.

Among the particles in the four choices, the charge-to-mass ratio is the greatest for electrons.

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Vladimir79 [104]

Answer:

1. The products of this reaction are ZnCl₂ and H₃PO₄.

2. 14.57 g.

Explanation:

<em>1. What would the products of this  reaction be?</em>

  • The balanced reaction between Zn₃(PO₄)₂ and HCl is represented as:

<em>Zn₃(PO₄)₂ + 6HCl → 3ZnCl₂ + 2H₃PO₄,</em>

It is clear that 1.0 mol of Zn₃(PO₄)₂ reacts with 6.0 mol of HCl to produce 3.0 mol of ZnCl₂ and 2.0 mol of H₃PO₄.

So, the products of this reaction are ZnCl₂ and H₃PO₄.

<em>2. If we produced 13.05 g of H₃PO₄, how many grams of  hydrochloric acid would be need to start with?​</em>

  • Firstly, we should get the no. of moles (n) of 13.05 grams of H₃PO₄:

n = mass/molar mass = (13.05 g)/(97.994 g/mol) = 0.1332 mol.

<u><em>Using cross-multiplication:</em></u>

6.0 mol of HCl needed to produce → 2.0 mol of H₃PO₄, from stichiometry.

??? mol of HCl needed to produce → 0.1332 mol of H₃PO₄.

∴ The no. of moles of HCl needed = (6.0 mol)(0.1332 mol)/(2.0 mol) = 0.3995 mol.

∴ The mass of HCl needed = n*molar mass = (0.3995 mol)(36.46 g/mol) = 14.57 g.

<em>So, the grams of  hydrochloric acid would be need to start with = 14.57 g.</em>

3 0
3 years ago
Which expression has a value of 10
AlexFokin [52]
The answer to this question B (10+10)/(5-3)
7 0
2 years ago
The amount of stored chemical energy is what determines the temperature of a substance
Setler79 [48]

Answer:

False

Explanation:

Temperature is the degree of hotness or coldness of a body. Temperature is as a result of how much heat a body has. Heat is a form of energy called thermal energy. Heat can be transferred from one body to another as a result of differences in temperature between two bodies.

Chemical energy does not determine the temperature of a body. It is the amount of heat it contains.

3 0
2 years ago
Read 2 more answers
What is the volume of an 2.3 solution with 212 grams of calcium chloride dissolved in it
Travka [436]

830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL

I am guessing that the concentration of your solution is 2.3 mol/L.

a) Moles of CaCl2

MM of CaCl2 = 110.98 g/mol

Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)

= 1.910 mol CaCl2

b) Volume of solution

V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution

= 830 mL solution


5 0
3 years ago
Does the antifreeze you put in a car radiator have a lower or higher freezing point than water
saveliy_v [14]
Hello!
Antifreeze says it in the name. This means that it helps prevent freezing. The liquid that would freeze if you wouldnt use the antifreeze is water. This means that the antifreeze has to have a higher freezing point then water, because otherwise it would only freeze faster!

Hope this helped you!
7 0
2 years ago
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