Question

Suppose now that you wanted to determine the density of a small crystal to confirm that it is silicon. From the literature, you know that silicon has a density of 2.33 . How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of ( = 1.492 g/mL) and ( = 2.890 g/mL)? (Note: 1 mL = 1 Cm^3)
V(CHCl3)=

V(CHBr3)=

Answer 1

Answer:

CHCL3= 11.73 mL

CHBr3= 8.268 mL

Explanation:

Let x be the mL of CHCl3 and y be the mL of CHBr3, then we have:

y+x = 20 mL

1.492x+2.89y=2.07* 20.0 mL