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mote1985 [20]
2 years ago
7

Does alcohol affect enveloped or naked viruses more

Chemistry
1 answer:
slega [8]2 years ago
7 0

Answer:

the protein capsid of naked  viruses is less susceptible to environmental .  condition

Explanation:

because the envelop is made in part of phospholipids. once the envelop is lysed ,the virus loses its functiovnal receptors and still able to infect susceptible cells.

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1. The maximum recommended amount of citric acid (H3C6H5O7; the 3 hydrogens listed first are the acidic hydrogens – the only hyd
Lisa [10]

The density has been given as the mass of the substance per volume of the solution. The mass of citric acid in the bottle has been 1.22 grams.

<h3>What is percent mass?</h3>

Percent mass can be given as the mass of substance in the total mass of the solution.

The volume of the face serum has been 250 mL, and the density is 0.979 g/mL.

The mass of face serum in the bottle has been:

\rm Density=\dfrac{Mass}{Volume}\\ 0.979\;g/mL=\dfrac{Mass}{250\;mL}\\ Mass=244.75\;g

The total mass of face serum has been 244.75 grams.

The percent mass of citric acid in face serum is 0.5%. This states the presence of 0.5-gram citric acids in 100 grams sample.

The mass of citric acid in the face serum sample is given as:

\rm 100\;gram\;sample=0.5\;g\;H_3C_6H_5O_7\\\\244.75\;grams\;sample=\dfrac{0.5}{100}\;\times\;244.75\;grams\; H_3C_6H_5O_7\\\\244.75\;grams\;sample=1.22\;grams\;H_3C_6H_5O_7

The mass of citric acid present in 250 mL serum sample has been 1.22 grams.

Learn more about percent mass, here:

brainly.com/question/5394922

3 0
2 years ago
Calculate the molar mass of PbSo3
vovikov84 [41]

Answer:

Lead sulfite is the inorganic compound with the formula PbSo3 or O3PbS.

Explanation:

8 0
2 years ago
According to the following balanced equation, 2 formula units of Iron (III) Oxide (Fe2O3) can be formed by reacting 4 atoms of i
-Dominant- [34]
You have to use Avogadro's number (6.02x10^23 molecules/mole) to find the number of moles each reactant starts off with.
moles of Fe and O₂:
12 atoms/(6.02x10^23 atoms/mole)=1.99x10^-23 mol Fe
6 molecules/(6.02x10^23 molecules/mole)=9.967x10^-24 mol <span>O₂
</span>Then you find the limiting reagent by finding how much product each given amount of reactant can make.  Which ever one produces the least amount of product is the limiting reagent.
amount of Fe₂O₃ produced:
<span>(1.99x10^-23 mol Fe)x(2mol/4mol)= 9.967x10^-24mol Fe</span>₂O₃<span> 
</span>(9.967x10^-24 mol O₂)x(2mol/3mol)= 6.645x10^-24 mol Fe₂O₃<span> 
</span>since oxygen produces the leas amount of product, oxygen is the limiting reagent.  since we know that oxygen is the limiting reagent we can use the amount of product formed with oxygen to find the amount of iron used.
6.645x10^-24 mol Fe₂O₃x(4mol/2mol)=1.329x10^-23 mol Fe consumed
<span> find the amount left over by subtracting the original amount of Fe by the amount consumed in the reaction.
</span>1.993x10^-23-1.329x10^-23= 6.645x10^-23mol Fe left
 find the number of atoms by multiplying that by Avogadro's number.
<span>(6.645x10^-23mol)x(6.02x10^23 atoms/mol)=4 atoms
</span>therefore 4 atoms of Fe will be left over after the reaction happens.

I hope this helps.
8 0
2 years ago
Read 2 more answers
How any moles of H2O will be produced from 12.3 moles of HCL reacting with Ca(OH)2?
stiks02 [169]

Answer:

\large \boxed{\text{12.3 mol HCl}}  

Explanation:

We need a balanced chemical equation with moles.

            2HCl +Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

n/mol:    12.3

The molar ratio is 2 mol H₂O:2 mol HCl.

\text{Moles of H$_{2}$O} = \text{12.3 mol HCl} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{2 mol HCl}} = \textbf{12.3 mol HCl}\\\\\text{The reaction produces $\large \boxed{\textbf{12.3 mol HCl}}$}

3 0
3 years ago
How many molecules are in 5 moles of O2?
SVETLANKA909090 [29]

Answer: 6.02 × 10^24

Explanation:

7 0
2 years ago
Read 2 more answers
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