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omeli [17]
4 years ago
10

Help, please and explain

Physics
1 answer:
11Alexandr11 [23.1K]4 years ago
5 0
We could tell a force is acting on an object if the object is being pushed, pulled, or moved in any way
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lab safety test Safety goggles and an apron must be worn when handling chemicals labeled corrosive because they:________.
Sunny_sXe [5.5K]

Answer:

The terms of biosafety in a laboratory require that the person must not have the eyes and skin exposed.

Explanation:

A corrosive substance is a substance that can damage a surface when they come into contact.

These substances represent a danger in people since they can burn the eyes, the skin, and the inside of the body since the inhalation of gases can burn the respiratory tract.

These chemical burns can be avoided by properly following the biosafety protocol that a laboratory requires the use of masks, goggles, gloves, and an apron or lab coat.

5 0
3 years ago
What is the internal energy of 3.00 mol of N2 gas at 25 degrees C? To solve this problem, use the equation: U electronic gas = 5
allochka39001 [22]

<u>Given data</u>

Determine Internal energy of gas N₂,  (U) = ?

Temperature (T) = 25° C

                          = 25+273 = 298 K,

Gas constant (R) = 8.31 J/ mol-K ,

Number of moles (n) = 3 moles,

<u>Internal energy of N₂ </u>

Internal energy is a property of thermodynamics, the concept of internal energy can be understand by ideal gas. For example N₂, the observations for oxygen and nitrogen at atmospheric temperatures,  f=5,  (where f is translational  degrees of freedom).

       So per kilogram of gas,

          The internal energy (U) = 5/2 .n.R.T

                                                  = (5/2) × 3 × 8.31 ×298

                                                  = 18572.85 J

<em>The internal energy of the N₂ is 18,572.85 J and it is approximately equal to 18,600 J given in the option B.</em>

 



8 0
3 years ago
Read 2 more answers
a body is projected at an angle of 30 degrees to the horizontal with a velocity of 15m/s, calculate the time it takes to reach t
andreev551 [17]

Explanation:

The vertical component the velocity of the projectile is 15 m/s x sin 30 = 7.5 m/s.

The body is accelarating downwards at 10 m/s^2.

This means that every second its upward velocity reduces by 10 m/s.

So if the body is travelling upwards at 7.5 m/s then how long does it take for the velocity to become 0?

(7.5 m/s) / (10 m/s^2) = 0.75 s

3 0
3 years ago
A boat initially traveling at 10. meters per second accelerates uniformly at the rate of 5.0 meters per second2 for 10. seconds.
guajiro [1.7K]
The initial speed of the boat is v_0=10 m/s
and its acceleration is a=5.0 m/s^2
Since the boat is moving by uniform accelerated motion, the distance covered by the boat in a time t=10 s is given by:
S(t)=v_0 t +  \frac{1}{2}at^2 = (10 m/s)(10 s)+ \frac{1}{2}(5m/s^2)(10s)^2 =350 m
So, the boat covers a distance of 350 m in 10 seconds.
4 0
3 years ago
Unpolarized light is incident upon two polarization filters that do not have their transmission axes aligned. If 21% of the ligh
Debora [2.8K]

Answer:

49.6°

Explanation:

I_0 = Unpolarized light

I_2 = Light after passing though second filter = 0.21I_0

Polarized light passing through first filter

I_1=\frac{I_0}{2}

Polarized light passing through second filter

I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow 0.21I_0=\frac{I_0}{2}cos^2\theta\\\Rightarrow cos^2\theta=\frac{0.21I_0}{\frac{I_0}{2}}\\\Rightarrow cos\theta=\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{0.21\times 2}\\\Rightarrow \theta=cos^{-1}\sqrt{0.42}\\\Rightarrow \theta=49.6^{\circ}

The angle between the two filters is 49.6°

5 0
4 years ago
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