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3 years ago

6

How can magnetic properties of a magnet be destroyed

1 answer:

uranmaximum [27]3 years ago

5 0

Answer:

heat, I think

when quenching knife blades you heat them up until they are no longer magnetic

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If electrical energy costs 7¢/kW•h, calculate

il63 [147K]

Answer:

10 minutes =(1/6)th of an hour

cost of running it for an hour = 0.09*7=0.56 c

in 10 min the cost should be (1/6)*0.56c=0.08c

Explanation:

Your scanner power is 15W so, it will consume 15*60=90Wh of electricity in an hour. that is 0.09KWh.

So, cost of running it for an hour = 0.09*7=0.56 c

Which means that in 10 min the cost should be (1/6)*0.56c=0.08c

4 0

3 years ago

How much min the basketball 1 player play

Sedbober [7]

Answer:

A professional basketball game depends on the association presiding over the game. An NBA game lasts for 48 minutes whereas FIBA games take 40 minutes. The total time taken to play for any specialized game is over 2 hours 15 minutes. The time includes the time disruptions like fouls, timeouts, and breaks.

<em>I hope it helps you...</em>

3 0

2 years ago

A 15.0 mW laser puts out a narrow beam 2.00 mm indiameter.

Murljashka [212]

Answer:

1341.03 V/m

Explanation:

The power output per unit area is the intensity and also the is the magnitude of the Poynting vector.

$S = \frac{P}{A}$ = cε₀ $E^{2} _{rms}$

⇒ $\frac{P}{A}$ = cε₀ $E^{2}_{rms}$

Where;

P is the power output

A is the area of the beam

c is speed of light

ε₀ is permittivity of free space 8.85 × 10⁻¹² F/m

$E_{rms}$ is the average (rms) value of electric field

Making electricfield $E_{rms}$ the subject of the equation

$E^{2}_{rms}$ = P / Acε₀

$E_{rms}$ = √(P / Acε₀)

But area A = πr²

$E_{rms}$ = √(P / πr²cε₀)

Given:

Output power, P = 15 mW = 0. 015 W

Diameter, d = 2 mm = 0.002 m

⇒ Radius, $r = \frac{d}{2} = \frac{0.002}{2} = 0.001 m$

Solving for average (rms) value of electric field;

$E_{rms} = \sqrt{\frac{0.015 W}{\pi * (0.001 m)^2 * (3 * 10^8 m/s) * (8.85 * 10^-12) C^2/Nm^2} }$

$E_{rms}$ = 1341.03 V/m

6 0

3 years ago

The mass of the sun is 1.99x10^30 kg . Jupiter is 7.79x10^8 km away from the sun and the mass of 1.90x10^27 kg

maks197457 [2]

Question is missing:

"What is the gravitational force between the Sun and Jupiter?"

Answer:

$4.16\cdot 10^{23} N$

Explanation:

The gravitational force between two objects is given by

$F=G\frac{m_1m_2}{r^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

In this problem, we have

$m_1 = 1.99\cdot 10^{30} kg$ is the mass of the sun

$m_2 = 1.90\cdot 10^{27} kg$ is the mass of Jupiter

$r=7.79\cdot 10^8 km = 7.79\cdot 10^{11} m$ is their separation

Solving the equation, we find

$F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(1.90\cdot 10^{27})}{(7.79\cdot 10^{11})^2}=4.16\cdot 10^{23} N$

6 0

2 years ago

Why do high-altitude clouds tend to appear before a warm front arrives in a region?

Ilia_Sergeevich [38]

Answer:

Global Warming

Explanation:

That's why

8 0

2 years ago

Read 2 more answers