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3 years ago

Joan purchased a large, tough cut of beef. To make the meat more tender what should she do

Physics

1 answer:

r-ruslan [8.4K]3 years ago

4 0

Answer:

She should braise it

Explanation:

Joan purchased a large, tough cut of beef. To make the meat more tender, she should braise it.

Braising begins with dry heat and ends with moist heat. At high temperatures, beef is seared in a heavy-bottomed Dutch oven to attain a caramelized crust. Then cover and finish cooking in a liquid at lower temperatures.

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Two identical blocks are connected to opposite ends of a compressed spring. the blocks initially slide together on a frictionles

lana66690 [7]

Answer:

v to the right.

Explanation:

If there is no external force on the system, then the velocity of the center of mass is constant.

The initial velocity of center of mass is v to the right. Therefore, the velocity of the center of mass at any point is v to the right.

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3 years ago

Explain how you know that gasoline burning in a car engine is a chemical change.?

polet [3.4K]

Burning, in general, is a chemical change.
Why?
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2 years ago

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If an ocean wave has a frequency of 2 waves/s and a speed of

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Answer:2m

Explanation:

Wavelength=velocity/frequency

Wavelength=4/2=2m

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2 years ago

A scientist hypothesizes that the temperature at which an turtle's egg is incubated

just olya [345]

Answer:

thw temperature of the male will be higher than that of the female.

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3 years ago

The carbon isotope 14C is used for carbon dating of archeological artifacts. 14C(mass 2.34×10−26kg) decays by the process known

Nookie1986 [14]

Answer:

2240.92365 m/s

Explanation:

$m_1$ = Mass of electron = $9.11\times 10^{−31}\ kg$

$v_1$ = Speed of electron = $5.7\times 10^7\ m/s$

$p_2$ = Neutrino has a momentum = $7.3\times 10^{-24}\ kg m/s$

M = total mass = $2.34\times 10^{-26}\ kg$

In the x axis as the momentum is conserved

$Mv_x=m_1v_1\\\Rightarrow v_x=\dfrac{m_1v_1}{M}\\\Rightarrow v_x=\dfrac{9.11\times 10^{−31}\times 5.7\times 10^7}{2.34\times 10^{-26}}\\\Rightarrow v_x=2219.10256\ m/s$

In the y axis

$Mv_y=p_2\\\Rightarrow v_y=\dfrac{p_2}{M}\\\Rightarrow v_y=\dfrac{7.3\times 10^{-24}}{2.34\times 10^{-26}}\\\Rightarrow v_y=311.96581\ m/s$

The resultant velocity is

$R=\sqrt{v_x^2+v_y^2}\\\Rightarrow R=\sqrt{2219.10256^2+311.96581^2}\\\Rightarrow R=2240.92365\ m/s$

The recoil speed of the nucleus is 2240.92365 m/s

3 0

3 years ago