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Licemer1 [7]
3 years ago
10

Joan purchased a large, tough cut of beef. To make the meat more tender what should she do

Physics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

She should braise it

Explanation:

Joan purchased a large, tough cut of beef. To make the meat more tender, she should braise it.

Braising begins with dry heat and ends with moist heat. At high temperatures, beef is seared in a heavy-bottomed Dutch oven to attain a caramelized crust. Then cover and finish cooking in a liquid at lower temperatures.

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Solve a hollow steel shaft has an outside diameter of 100mm and inside diameter of 75 mm.the shaft is subjected to a pure torque
FrozenT [24]
  • The maximum shearing stress in hollow shaft is 66.125 MPa.
  • The magnitude of angle of twist is 0.0279 rad.
  • The power generated by the shaft is  157 kW.

<h3>What is power ?</h3>

Power in a rotating body like shaft is the product of Torque and the angular speed of that shaft.

P = Tω

The Torque is related to the shearing stress is

T = π/16 xτ(Do³ -Di³)

* Given is the Torque T= 7.5 kN.m, the inner diameter Di = 0.075m, outer diameter Do= 0.1m

Then, the maximum shearing stress will be

7.5 x 10³ =  π/16 xτ x (0.1³ - 0.075³)

τ = 66.125 MPa

Thus, the shearing stress is 66.125 MPa.

* From the Torque equation

T/J = Gθ/l

Where, J = π/32 (Do⁴ -Di⁴) = 0.00000671 m⁴

l = length of shaft = 2m, modulus of rigidity G = 80GPa = 80x 10⁹ Pa.

Substitute the values, we get the angle of twist

7.5 x10³ /0.00000671 = 80x 10⁹xθ/2

θ = 0.0279 rad.

Thus, the angle of twist is0.0279 rad.

* Power generated by the shaft is

P = 2πNT/60

where N = revolution/ minute = 200

Put the values, we get

P =  2π x 200 x 7500/60

P = 157 kW.

Thus, the power generated is 157 kW.

Learn more about power.

brainly.com/question/15120631

#SPJ1

5 0
2 years ago
When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37° C) by warmin
Papessa [141]

Answer:

The number of liters of ice water is 11 L

Explanation:

Given data:

normal body temperature = 37°C

temperature of the ice water = 0°C

Cwater = specific heat of water = 4186 J/kg °C

Suppose the person drinks 1 L of cold water, then, the mass is 1 kg

The heat is:

Q_{water} =mC_{water} (T_{ice} -T_{body} )=1*4186*(0-37)=-154882J

The sign (-) indicates the energy lost by the metabolic process. If the Qwalk is 390 kilocalories, then the number of liters of ice water is equal to:

n=\frac{Q_{walk} }{Q_{water} } =\frac{390*4186}{154882} =10.54=11L

5 0
3 years ago
A string under a tension of 36 N is used to whirl a rock in a horizontal circle of radius 3.6 m at a speed of 16.12 m/s. The str
ExtremeBDS [4]

Answer:

6010.457N

Explanation:

Centripetal acceleration = a= V²/R

At a radius of 3.6m and velocity of 16.12m/s,

Acceleration is

a = 16.12²/ 3.6 = 72.182 m/s²

Force = Mass (m) * Acceleration (a)

36 = m * 72.182

m = 36/72.182

At breaking point

Radius = 0.468 m and Velocity = 75.1 m/s

a = V²/R = 75.1²/0.468

a = 12051.3 m/s

F = Mass(m) * Acceleration (a)

F = m * 12051.3

m = F/ 12051.3

Settings the ratio of mass equal

m = m

=> 36/72.182 = F/12051.3

F = 12051.3 * 36/72.182

F = 6010.457N

3 0
3 years ago
A ball of 12 kg is attached to a string of 0.8 meter spun at 4
lesantik [10]

Answer:

240 N

Explanation:

6 0
2 years ago
The force of gas particles against the walls of a container is called ________
Liono4ka [1.6K]

Answer:

the answer is pressure

8 0
3 years ago
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