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3 years ago

I think I pooped in my pants

Mathematics

2 answers:

Zolol [24]3 years ago

3 0

Answer:

lol

Step-by-step explanation:

open your mouth and make sound come out

Mila [183]3 years ago

3 0

Answer:

OOP- r.i.p your pants

Step-by-step explanation:

BUT I LIKE YOUR CUT G

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Find and simplify the difference quotient f(x + 1) – f(x) for the following function.

ra1l [238]

In your situation you said that

$f(x) = mx+b$
$m=0$

Putting those together, you'd have $f(x) = b$ because $0\cdot x+b=b$ .

To evaluate the difference quotient, first find each piece on it's own:

$f(x+1) = b$ because $f(x) = b$ no matter what your x-value is.
$f(x) = b$

So putting those together:

$f(x+1) - f(x) = b-b = 0$

Remember that the difference quotient is basically finding the slope of something. Since you were given that the slope is 0, the difference quotient should work out to match that.

3 0

3 years ago

Read 2 more answers

Meenu bought two fans for ₹1200 each. She sold one at a loss of 5% and the other at a profit of 10%. Find the selling price of e

Vinvika [58]

<h3><u>Solution: </u></h3>

Overall<u> </u>CP of each fan = ₹1200 .

One is sold at a loss of 5% .

( This means if CP is ₹100, SP is ₹95 ) .

• Therefore,When CP is ₹1200 , Then SP is ₹ 1140.

$= > \frac{95}{100} \times 1200 = 1140$

Also,Second fan is sold at a profit of 10% .

It means , If CP is ₹100 , SP is ₹110.

Therefore , When CP is ₹1200 , Then SP is ₹1320.

<u>• We need to find the combined CP and SP to say whether there was an overall profit or Loss.</u><u>.</u>

Total CP = ₹ 1200 + ₹ 1200 = ₹ 2400.
Total SP = ₹ 1140 + ₹ 1320 = ₹ 2460.

Since total SP > total CP , A profit of ₹ ( 2460 - 2400 ) or ₹60 has been made ..

<h3>Hope this helps you :)</h3>

4 0

3 years ago

Pleaseeee helpppp i’m not sure what this one is also please explain thanksss

AURORKA [14]

I think acute but I’m really not sure

5 0

3 years ago

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

3 years ago

(x² + x - 17) ÷ (x - 4)

ludmilkaskok [199]

Answer:
(X^2 + X-17) /x-4

5 0

3 years ago