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3 years ago

Help !!! with 14 please :))

Mathematics

1 answer:

BartSMP [9]3 years ago

3 0

Since p is an obtuse angle
& that it's between two acute angles

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Suppose M is the midpoint of line FG.

alukav5142 [94]

$A)\\|FM|=5y+13;\ |MG|=5-3y\\\\|FG|=|FM|+|MG|\\\\|FG|=(5y+13)+(5-3y)=2y+18\\\\B)\\|FM|=8a+1;\ |FG|=42\\\\|FG|=2|FM|\\\\2(8a+1)=42\\16a+2=42\ \ \ \ \ |subtract\ 2\ from\ both\ sides\\16=40\ \ \ \ \ |divide\ both\ sides\ by\ 16\\a=\frac{40}{16}\\a=\frac{5}{2}\\a=2.5$

6 0

3 years ago

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B2 to both sides of the equation in step 4,

Sladkaya [172]

Answer:

Step-by-step explanation:

I dont quite understand the problem but this is one way to solve it using completing the square:-

2x^2 + 8x - 12 = 0

2(x^2 + 4x) - 12 = 0

2((x + 2)^2 - 4) = 12

2(x + 2)^2 - 8 + 8 = 12 + 8

2(x + 2)^2 = 20

6 0

3 years ago

the school building was 98 feet long and 32 feet wide the last room in the building was an office and was 12 feet long what was

olga55 [171]

Answer:the height of the building is around 122 feet the distance would be about 300.2 feet

Please mark me brainlest

Step-by-step explanation:

8 0

2 years ago

2. A triangular pyramid begins with these coordinates:

vagabundo [1.1K]

The rule for the reflection is (x,y,z) → (-x,y,z) so P' = (1, 2, 0) for example.
<span>Then the rule is (x,y,z) → (x + 2, y + 4, z - 3) so P'' = (3, 6, -3) </span>

3 0

3 years ago

Break downs occur on a 20-years-old car with rate λ= 0.5 breakdowns/week. The owner of the car is planning to have a trip on his

KengaRu [80]

Answer: There is probability of 0.367 that there will be no breakdown on his car in the trip.

Step-by-step explanation:

Since we have given that

Mean (λ) = 0.5 breakdown per week

Number of weeks the owner of the car is planning to have a trip on his car for = 2 weeks

So, mean for 2 weeks would be

$0.5\times 2=1.0$

We need to find the probability that there will be no breakdown on his car in the trip.

Probability that there will be no breakdown on his car in the trip is given by

P(X=0) is given by

$\dfrac{e^{-\lambda}\lambda^k}{k!}\\\\=\dfrac{e^{-1}1^0}{0!}\\\\=0.367$

Hence, there is probability of 0.367 that there will be no breakdown on his car in the trip.

7 0

3 years ago