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strojnjashka [21]
2 years ago
10

Find the slope from the table.

Mathematics
1 answer:
Hunter-Best [27]2 years ago
3 0
The answer is c.
The slope is looking for how much the number changes for every x value. The x values in the table increase by 2 and the y values increase by 6. Using rise over run, this would mean that the slope is 6/2 which equals 3.
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A card is drawn at random out of a​ well-shuffled deck of 52 cards. Find the probability of drawing a six comma seven comma or e
Rina8888 [55]

Answer: \frac{3}{13}, or ~23.07%

Step-by-step explanation:

There are 52 cards in your average deck.

For this question, you need the numbers of the cards in the deck. There are four of each number from 2 through 10, and four aces, jacks, queens, and kings.

Considering there are four 6s, four 7s, and four 8s, there are 12 cards that fit the description.

Divide 12 by the total number of cards in the deck, 52, to get your answer.

8 0
3 years ago
Can someone help me with number 3, please
oksian1 [2.3K]

Answer:

E

Step-by-step explanation:

We can see that section E of the graph increases, but unlike section B it is much longer and, therefore, increases more slowly.

Hope this helps friend.

4 0
2 years ago
Read 2 more answers
Multiply 1/3 1/5<br><br>-1/10<br><br>-1/15<br><br>1/15<br><br>1/10​
defon

Answer:

1/337500

(Decimal: 0.000003)

Step-by-step explanation:

8 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
2 years ago
If the equation of a function is y = x2 – 5, what is the output when the input is -1?
Nimfa-mama [501]
The input is the y
y = x^2 - 5
plug in what we're given
-1 = x^2 -5
add 5 to both sides
4 = x^2 
take the square root of both sides
2 = x

Hope this helps :)

4 0
3 years ago
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