All categories

3 years ago

Estimate the sum of 487 and 310

2 answers:

8 0

487 is almost 500, so we will approximate 487 as 500.
310 is just over 300, so we will approximate 310 as 300.

300+500=800 (estimation)
310+487=797 (actual)

umka2103 [35]3 years ago

8 0

500+300=800
is the answer

You might be interested in

John spent $75 on a shopping trip for new clothes last week. He had expected to spend $100 on clothes. How much was the error in

Gre4nikov [31]

The answer is either c or b because i think they are the same

7 0

4 years ago

Work out 22% of 600 <br> I need help

Yanka [14]

Answer:

132

Step-by-step explanation:

$\frac{x}{600} = \frac{22}{100}$

X = 132

5 0

3 years ago

Read 2 more answers

A comedian knows eleven jokes. One joke is old, one joke is new, and the other jokes are somewhere between. If the order in wh

Nadya [2.5K]

Answer:

IDk some kind of riddle

8 0

4 years ago

Read 2 more answers

Convert the rational number below to a decimal. Round to the

masha68 [24]

Answer:

10.33

Step-by-step explanation:

$\frac{31}{3}$ is equal to 31 divided by 3, which is 10.33333333333333333...

Rounded to the nearest hundredth we get 10.33.

Hope this helps!

5 0

4 years ago

Using Pythagorean inequalities, determine which of the following sets of values can represent the lengths of the sides of an acu

seropon [69]

Answer:

Step-by-step explanation:

$a,\ b,\ c-\text{sides of a triangle}\\\\\text{If}\ a\leq b< c\ \text{and}\ a^2+b^2=c^2,\ \text{then it's the lengths of the sides of a right triangle}\\\\\text{If}\ a\leq b\leq c\ \text{and}\ a^2+b^2>c^2,\ \text{then it's the lengths of the sides of a acute triangle}\\\\\text{If}\ a\leq b< c\ \text{and}\ a^2+b^2$

$\text{Triangle condition:}\\\text{That each side has to be shorter than the sum of the other two sides}\\\text{and longer than their difference.}\\\\\text{If}\ a\leq b\leq c,\ \text{then}\ a+b>c.$

$--------------------------\\a.\\a=1,\ b=2,\ c=3\\\\a+b=1+2=3=c\\\\\text{These are not the lengths of the sides of the triangle.}\\----------------------------\\b.\\a=6,\ b=8,\ c=10\\\\a+b=6+8=14>10=c\qquad OK\\\\a^2+b^2=6^2+8^2=36+64=100\\\\c^2=10^2=100\\\\a^2+b^2=c^2\\\\\text{It's the right triangle.}\\----------------------------$

$c.\\a=6,\ b=7,\ c=8\\\\a+b=6+7=13>8\qquad OK\\\\a^2+b^2=6^2+7^2=36+49=85\\\\c^2=8^2=64\\\\a^2+b^2>c^2\\\\\text{It's the acute triangle.}\\----------------------------\\d.\\a=4,\ b=6,\ c=10\\\\a+b=4+6=10=c\\\\\text{These are not the lengths of the sides of the triangle.}$

6 0

3 years ago