Answer:
V1 = 3.09 L
Explanation:
Initial Pressure, P1 = 15.6 psi
Initial Volume, V1 = ?
Final Pressure, P2 = 25.43 psi
Final Volume, V2 = 1.895 L
The relationship between these quantities is given by boyles law;
V1P1 = V2P2
V1 = V2P2 / P1 = 1.895 * 25.43 / 15.6
V1 = 3.09 L
Given:
0.607 mol of the weak acid
0.609 naa
2.00 liters of solution
The solution for finding the ph of a buffer:
[HA] = 0.607 / 2.00 = 0.3035 M
[A-]= 0.609/ 2.00 = 0.3045 M
pKa = 6.25
pH = 6.25 + log 0.3045/ 0.3035 = 6.25 is the ph buffer prepared.
The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles
<u>Given data :</u>
Moles of strontium nitrate = 6.15 moles
<h3>Ionization of Strontium Nitrate </h3>
When strontium nitrate (
) is placed in water it will dissociates into its ions because strontium nitrate is an ionic compound.
Next step : Represent the ionization of strontium nitrate

From the Stoichiometry of the chemical reaction
I mole of strontium nitrate = 2 moles of Nitrate ions
6.15 mole of strontium nitrate = 2 * 6.15
= 12.3 moles of Nitrate
Hence we can conclude that The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles.
Learn more about Stoichiometry of chemical reaction : brainly.com/question/27058367
The balanced chemical reaction would be:
2SO2 + O2 = 2SO3
We are given the amount of oxygen to be used. We calculate as follows:
3.5 moles O2 ( 2 mol SO3 / 1 mol O2 ) = 7 mol SO3 is produced from the reaction.
Hope this answers the question. Have a nice day.