Answer:
0.56
Explanation:
From the formula;
0.693/t1/2 = 2.303/t log (Ao/At)
t1/2 = half life of the C-14 = 5730 y
t = time elapsed = 4800 y
At = Activity of C-14 at time t
Ao= Activity of a living C-14 sample
0.693/5730 = 2.303/4800 log (Ao/At)
1.2 * 10^-4 = 4.8 * 10^-4 log (Ao/At)
log (Ao/At) = 1.2 * 10^-4/4.8 * 10^-4
log (Ao/At) = 0.25
Ao/At = Antilog (0.25)
Ao/At = 1.778
Hence;
At/Ao = (1.778)^-1
At/Ao = 0.56
The substances that dissolves in water are called solute.
Answer:
15912 × 10∧-19 KJ
Explanation:
Given data;
frequency of photon = 2.4 × 10^18 1/s.
Planck's constant = 6.63 × 10∧-34 j.s
Energy = ?
Formula:
E = h × ν
E = 6.63 × 10∧-34 j.s × 2.4 × 10^18 1/s
E= 15.912 × 10∧-16 j
now we will convert the joule into kilo joule,
E = 15.912 × 10∧-16 j /1000 = 15.912 × 10∧-19 KJ
Answer:
The answer to your question is 100.8 g
Explanation:
Data
mass of Barium chloride = 90 g
mass of Barium sulfate = ?
Balanced chemical reaction
BaCl₂ + H₂SO₄ ⇒ BaSO₄ + 2HCl
Process
1.- Calculate the molar mass of BaCl₂ and BaSO₄
BaCl₂ = 137.3 + (2 x 35.5) = 208.3g
BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g
2.- Use proportions to find the mass of BaSO₄
208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄
90 g of BaCl₂ --------------------- x
x = (90 x 233.3) / 208.3
x = 20997/ 208.3
x = 100.8 g
3.- Conclusion
There will be produced 100.8 g of BaSO₄
2.52 answer=c. That is the pH.
