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JulsSmile [24]
3 years ago
12

Sperm and egg donation service agencies offer hope to infertile parents who hope to conceive their own children in the future. S

perm donation is a relatively easy process, requiring no more than an hour’s time. However, donating eggs is a rather complicated task, requiring months of hormone therapy and minor surgical procedures to retrieve the harvested eggs. In addition, drugs injected into women cause their ovaries to ovulate several eggs at once, greatly increasing the odds of developing cancer. To compensate for the ‘inconvenience’, women are given a large sum of money. Often, young, female college students are targeted for egg donations since they are considered more educated and healthier that their older female counterparts. Do you think females should be compensated for donating their eggs? Why or why not? Is it appropriate for egg donation agencies to advertise for potential egg donors on college campuses?
Biology
1 answer:
alisha [4.7K]3 years ago
7 0

Answer:

They should not be compensated because they do it out of free will and the eggs are valuable than any amount you can think of.

No.This may draw the students attention to the money they often give rather than their studies

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Where do many of the world's deserts lie?
Jlenok [28]

Answer:

Most of the world's deserts are located near 30 degrees north latitude and 30 degrees south latitude, where the heated equatorial air begins to descend

Explanation:

8 0
3 years ago
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The concentration of N2 in blood at 37 °C (body temperature) and atmospheric pressure (partial pressure of N2 = 0.80 atm) is 0.0
devlian [24]

Answer:

volume  = 0.285 L

Explanation:

Henry constant is given as

Henry constant  =  \frac{C}{P}

Where C  is concentration

P is atmospheric pressure

Henry\ constant = \frac{0.00056}{0.80} = 0.0007 M/atm

when atmospheric pressure 4 atm

solubility = K_H\times P

              = 0.0007 \times 4 = 0.0028 M

In 5 litere blood , moles of N_2 = Molarity \times volume

                                                     = 0.0028 \times 5 = 0.014

At surface moles  = 0.0056 \times 5 = 0.0028

Moles of N_2 release = 0.014 - 0.0028 = 0.0112

Mass of N_2 = 0.0112 \times 28 = 0.314 g

T = 37 + 273 = 310 K

VOLUME = \frac{nRT}{P}

= \frac{0.0112\times 0.0821\times 310}{1}

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6 0
3 years ago
What two characteristics do fungi lack that forced them to become decomposers
Artist 52 [7]
Fungi are decomposers, they obtain their food from dead organic matters. Fungi obtain their nutrient this way because they can not produce their own food. To produce their own food they need chloroplast in their cells to obtain energy from the sun. And they also need the ability to fix nitrogen which they will incorporate into the food they produce. Because they lack the ability to do this thing, they have to adapt to eating dead materials. <span />
8 0
4 years ago
A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by
bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that  <em>the</em><em> probability</em><em> that, given enough time, all tigers in the population will have horizontal stripes is</em><em> 30% = 0.3.</em>

--------------------------

<u>Available data:</u>

  • Population size, N = 100 tigers
  • Number of Tigers with horizontal stripes = 30
  • Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

--------------------------

You can learn more about Hardy-Weinberg equilibrium at

brainly.com/question/12724120?referrer=searchResults

brainly.com/question/9870841?referrer=searchResults

brainly.com/question/419732?referrer=searchResults

brainly.com/question/13603001?referrer=searchResults

brainly.com/question/5028378?referrer=searchResults

6 0
3 years ago
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