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Andreas93 [3]
3 years ago
7

8x10 with the power of 0

Mathematics
2 answers:
Tpy6a [65]3 years ago
7 0

Since you gave no parenthesis: Remember to follow PEMDAS. Note that anything with the power of 0, the answer will become 1

10^0 = 1

8 x 1 = 8

8 is your answer

hope this helps

Scrat [10]3 years ago
7 0

the answer is eight because 10 is to the power of 0 which basically is 10 times 0 which is zero and 8 x 0 is 8

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Which expression has a value of 66? A. (16 ÷ 3.2) × 2 + 0.2 × (8 + 82) B. [(16 ÷ 3.2) × (2 + 0.2)] × 8 + 82 C. 16 ÷ [(3.2 × 2) +
Setler [38]

Answer: none

Step-by-step explanation:

(A)

(16÷32/10) ×2 + 0.2×(90)

Using bodmas principle ; solve bracket

(16×10/32)×2 + (2/10×90)

10+18 =28

(B)

{(16÷32/10) × (2+2/10)} ×90

Open brackets

{(16×10/32) × (22/10)} ×90

(5×11/5) ×90

11×90 = 990

(C)

16÷{(32/10×2) + (2/10×8)} +82

Open brackets, solve division first, dolled by addition

16÷(32/5 + 8/5) +82

16÷(40/5) +82

16÷8 +82

2+82= 84

(D)

[16÷(32/10 ×2) + 0.2× (90)]

16÷ (32/5) + 2/10 ×90

Solve division

16×5/32 + 18

5/2 + 18

L.c.m of denominator (2&1) =2

(5+36) / 2 = 41/2

=20.5

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3 years ago
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Step-by-step explanation: hope it helps :)

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In a coin game, you repeatedly toss a biased coin (0.4 for head, 0.6 for tail). Each head represents 3 points and tail represent
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Answer:

See answer in explanation

Step-by-step explanation:

State: current points if stop plus a terminal state, that is, 0,1,2,3,4,5,6,7,DONE

Action: Toss, Stop

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Transition function:

T(Si , TOSS, Si+3) = 0.4 if i < 3

T(Si , TOSS, DONE) = 0.4 if i ≥ 3

T(Si , TOSS, Si+1) = 0.6 if i < 7

T(Si , TOSS, DONE) = 0.4 if i = 7

T(Si , STOP, DONE) = 1

Reward function:

R(Si , TOSS, ANY ) = 0

R(Si , STOP, DONE) = i

R(DONE, STOP, DONE) = 0

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You should include the steps of value iteration. The value iteration will converge at

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