6 pairs of shorts, for a
"s" dollars. A blazer costs 3 times as much, she bought one. The total was 139.50
6s + 3(6s) = 139.50
6s + 18s = 139.50
25s = 139.50 Divide everything by 25,
s = 5.58, which is how much the shorts were. Now for the blazers ;
It said they were three times the cost of shorts, if shorts are 5.58, it is 3*5.58.
3s
3(5.58)
16.74
The blazer cost 16.74
# 4 is a function because all the x numbers are only used once
Answer:
so what you do is you divide 30 by 4.5 then when you get the density you divide that by the 10 pennies so you get the density of 1 penny
Step-by-step explanation:
Answer:
Option C
Step-by-step explanation:
The chi square test of independence is used to determine if there is a significant association between two categorical variables from a population.
It tests the claim that the row and column variables are independent of each other.
The degrees of freedom for the chi-square are calculated using the following formula: df = (r-1) (c-1) where r is the number of rows and c is the number of columns.
<em><u>HEY</u></em>
<em><u>For variables at ordinal level use </u></em><em><u>Spearman's</u></em><em><u> </u></em><em><u>correlation</u></em><em><u>. However, Chi-Square is also suitable to use for test of significance with cross tabulation of ordinal level data</u></em>
<em><u>thank </u></em><em><u>me </u></em><em><u>later</u></em>
<em><u>carryonlearing</u></em>
<em><u>✨</u></em><em><u> jufaith </u></em><em><u>✨</u></em>
