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jolli1 [7]
4 years ago
13

A binomial probability experiment is conducted with the given parameters. Use technology to find the probability of x successes

in the n independent trials of the experiment. n=9​, p=0.45​, x<4
Mathematics
1 answer:
serg [7]4 years ago
5 0

Answer:

<em>The probability of  successes  </em> P( x < 4 ) = 0.36138

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given 'n'=9

<em>The probability of success 'p' = 0.45</em>

<em>                                             q = 1-p = 1-0.45 = 0.55</em>

<em>Let 'X' be the random variable in Binomial distribution</em>

<em></em>P(X=r) = n_{C_{r} } p^{r} q^{n-r}<em></em>

<em></em>n_{C_{r} } = \frac{n!}{(n-r)!r!}<em></em>

<em></em>

<u><em>Step(ii):-</em></u>

<em>The probability of x successes in the n independent trials of the experiment</em>

P(x

              = = 9_{C_{0} } (0.45)^{0} (0.55)^{9-0}+9_{C_{1} } (0.45)^{1} (0.55)^{9-1}+9_{C_{2} } (0.45)^{2} (0.55)^{9-2}+9_{C_{3} } (0.45)^{3} (0.55)^{9-3}By using factorial notation

<em></em>n_{C_{r} } = \frac{n!}{(n-r)!r!}<em></em>

9_{C_{0} } = 1 , 9_{C_{1} } = 9 , 9_{C_{2} } = 36, 9_{C_{3} } = 84

P( x < 4 ) = (0.55)⁹ + 9(0.45) (0.55)⁸ + 36 (0.45)² (0.55)⁷ +84 (0.45)³ (0.55)⁶

P( x < 4 ) = 0.004605+0.03391 + 0.1109855+ 0.21188

P( x < 4 ) = 0.36138

<u><em>Final answer:-</em></u>

<em>The probability of  successes  </em> P( x < 4 ) = 0.36138

<em></em>

             

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