The lines with a slope of 0 are horizontal lines because all the points on the line have the same y-coordinate on a graph. Using the slope formula on the line will give you 0.
2(x-6y+4z=2)
2x+4y-8z=16
2x-12y+8z=4
2x+4y-8z=16
4x-8y=20
x-2y=5
4x-8y=20
-4x+8y=-20
infinite many solutions

a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =

=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34
Answer:
Step-by-step explanation:
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Good evening ,
_______________
The right answer is D
We should rotate the R point 3/4 a circle clockwise so it falls on D point.
:)