The answer is C. The modem does not contain enough bandwidth to handle modern video streaming.
I use an app called codechecker that helps with me having issues like that cause 99% of the time I'll mess it up.
<span>Slow shutter speeds allow more light into the camera sensor and are used for low-light and night photography, while fast shutter speeds help to freeze motion. Examples of shutter speeds: 1/15 (1/15th of a second), 1/30, 1/60, 1/125. Aperture – a hole within a lens, through which light travels into the camera body.
Hope this helps : )
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Answer:
En carpintería se utilizan martillo, cinta métrica, escuadras, niveles de burbuja, navaja, herramientas de marcado, destornilladores y sierra circular.
Explicación:
Las herramientas manuales utilizadas en carpintería son martillos, cinta métrica, escuadras, niveles de burbuja, navaja, herramientas de marcado, destornilladores y sierras circulares, etc. Con martillos se pueden unir dos piezas de madera. La cinta métrica se utiliza para medir. Las herramientas manuales que se utilizan para la herrería son martillos de mano, mazos, cinceles, punzones, punzones y una selección de tenazas con brocas, etc. Estas herramientas se utilizan para cambiar la forma después de estar blandas debido al calentamiento.
<u>Answer:</u>
<em>void main ( ) </em>
<em> { </em>
<em> int counter; </em>
<em> cout<<""Even numbers between 1 to 20 are:""<<endl ; </em>
<em> //Method 1
</em>
<em> for (counter = 1; counter <= 20; counter++) </em>
<em> { </em>
<em> if ( counter%2 == 0) </em>
<em> {
</em>
<em> cout<<counter<<""\t""<<endl ; </em>
<em> } </em>
<em> } </em>
<em>//Method 2 – simplest one
</em>
<em>for (counter = 2; counter <= 20;) </em>
<em> { </em>
<em> cout<<counter<<""\t""<<endl ; </em>
<em>counter = counter + 2;
</em>
<em> </em>
<em> }
</em>
<em>
</em>
<em> return 0; </em>
<em>}
</em>
<u>Explanation:</u>
In this, Method 1 runs a for loop and check whether each number is divided by 2. If yes, then printed otherwise it is skipped.
In the second method, it runs for loop only for even numbers. <em>This is obtained by incrementing the counter by 2.
</em>