so 2 is the remainder of 4
the length of the earthworm to the near<span>est inch is c.3/4 </span>
If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
y = 6/2 = 3
Therefore, m<TSU = 4(3) + 11 = 12 + 11 = 23
Answer:
-x2+25x-5
Step-by-step explanation:
7x+2x−3x2+9x+5x+8x2−6x2+2x−5
=−x2+25x−5