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JulsSmile [24]
4 years ago
15

A roller coaster starts from rest at the top of a drop and accelerates at a rate of 5.0 m/s2 for 2.0 sec. When it

Physics
1 answer:
balandron [24]4 years ago
6 0

Answer: 2.5 m/s.

Explanation:

At rest, acceleration = 0

At the top of the drop acceleration = 5.0 m/s2

Rate of acceleration = (5.0 m/s2 - 0) = 5.0m/s^2

Time taken for travel = 2.0 sec

At the bottom of the drop point, the velocity will be (Change in acceleration / time taken)

i.e (5.0 m/s2 / 2.0 seconds)

= 2.5 m/s

Thus, the velocity of the rollercoaster will be 2.5m/s.

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Three ropes A, B and C are tied together in one single knot K. (See figure.)
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The tension in the rope B is determined as 10.9 N.

<h3>Vertical angle of cable B</h3>

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tan θ = (2)/(5)

tan θ = 0.4

θ = arc tan(0.4) = 21.8 ⁰

<h3>Angle between B and C</h3>

θ = 21.8 ⁰ + 21.8 ⁰ = 43.6⁰

Apply cosine rule to determine the tension in rope B;

A² = B² + C² - 2BC(cos A)

B = C

A² = B² + B² - (2B²)(cos A)

A² = 2B² - 2B²(cos 43.6)

A² = 0.55B²

B² = A²/0.55

B² = 65.3/0.55

B² = 118.73

B = √(118.73)

B = 10.9 N

Thus, the tension in the rope B is determined as 10.9 N.

Learn more about tension here: brainly.com/question/24994188

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Two technicians are discussing how a clutch disengages. Technician A says a gap on each side of the clutch disk facing when dise
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