The maximum velocity in a banked road, ignoring friction, is given by;
v = Sqrt (Rg tan ∅), where R = Radius of the curved road = 2*1000/2 = 1000 m, g = gravitational acceleration = 9.81 m/s^2, ∅ = Angle of bank.
Substituting;
30 m/s = Sqrt (1000*9.81*tan∅)
30^2 = 1000*9.81*tan∅
tan ∅ = (30^2)/(1000*9.81) = 0.0917
∅ = tan^-1(0.0917) = 5.24°
Therefore, the road has been banked at 5.24°.
Answer:
the distance between adjacent fringes is increased by a factor o 2
Explanation:
To find how the distance between fringes is modified you can use the following formula for the calculation of the distance between fringes:
D: distance to the screen
d: distance between slits
λ: wavelength of the light
if d is decreased by a factor of 2, that is d'=1/2d, you have:
hence, the distance between adjacent fringes is increased by a factor o 2
Answer:infrared radiation
Explanation:
Most remote control uses infrared radiation
Answer:
The new speed is 56.25 miles/hour.
Explanation:
Since speed = distance/time;
time = distance/speed.
While driving at 50 miles/hour, time taken for one to complete 1 mile is (1/50) hour
(1/50) hour = (1/50) × 3600s = 72 seconds.
So, if this time to complete 1 mile (72 seconds) is reduced by 8 seconds,
New time to complete 1 mile will be = 72 - 8 = 64 seconds = (64/3600) hour = 0.0178 hour
New speed would be = (1 mile/64 seconds) = (1 mile/0.0178 hour) = 56.25 miles/hour.
Hope this Helps!!!
