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Natali5045456 [20]
4 years ago
6

The captain told the passengers that the plane is flying at 450 miles per hour this information describes the plane

Physics
2 answers:
xz_007 [3.2K]4 years ago
8 0
Speed, why velocity has direction acceleration Is a change in speed and it doesn't give a direction so it's speed
Masja [62]4 years ago
7 0

Answer:

The correct answer is speed.

Explanation:

Time rate of change in distance is called as speed. On the other hand, time rate of change in displacement is called velocity. The captain told time rate of change in distance (450 miles/hour) because he did not mention the direction. Hence, 450 miles/hour describes the speed of the plane. We do not identify any relation of this information with direction and acceleration.

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What is occurring in the umbra?
matrenka [14]

Answer:

A. a total solar eclipse

Explanation:

During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth

3 0
3 years ago
You grab a hot cookie sheet out of the oven this is an example of ______ energy transfer.
Maru [420]
I would say Conduction because you are touching the cookie sheet, even though it is hot (so heat) you are physically touching it so it would not be radiation
6 0
3 years ago
A 30⁰ 5.2 km 3.7 km FIGURE 1 40⁰ B x FIGURE 1 shows two displacement vector A and B. Determine the magnitude and direction of th
Alika [10]

The resulatant displacement will be 8.60m

What is displacement?

Displacement is the shortest path covered by an individual.

We have given the distance 5.2km and 3.7Km.

The resultant will be given in the photo



to learn more about displacement click brainly.com/question/13413762

8 0
2 years ago
Bro why cant I post this T-T
Leni [432]

Answer: 12.0 m/s^2

Explanation:

Let \alpha be the angular acceleration of the end of the rod

Taking torque about the link, we have:

\tau = W \times OM\\ or\\ \tau = mg\times \left(\dfrac{L}{2}\right)\sin 55^\circ ....(i)

Torque is also given in terms of moment of inertia of the rod and its angular acceleration i.e.

\tau = I_{rod}\ \alpha......(ii)

From equations (i) and (ii) we have:

mg\times \left(\frac{L}{2}\right)\sin 55^\circ = \left(\frac{mL^2}{3}\right)\alpha\ \ \ \ \ \ \ (\because I_{rod} = \dfrac{mL^2}{3}) \\ \\ \alpha = \left(\frac{3g}{2L}\right)\sin 55^\circ\\ \\ \alpha = \left(\frac{3\times 9.8}{2\times 2.4}\right)\sin 55^\circ\\ \\ \boxed{\alpha = 5.02\ rad/s^2} }

The acceleration of the end of the rod farthest from the link is given by:

a = L\alpha\\ \\ a = (2.4\ m)(5.02\ rad/s^2)\\ \\ \boxed{a = 12.0\ m/s^2}

7 0
2 years ago
Find the average braking force of a 1000 kg car moving at 10 m/s braking to a stop in 5 s.
Verdich [7]

Answer:

-2000 N

Explanation:

To solve the problem, we can use the impulse theorem, which states that the impulse is equal to the change in momentum of the car:

I = \Delta p\\F \Delta t = m \Delta v

where

F is the average breaking force

\Delta t = 5 s is the stopping time

m = 1000 kg is the mass of the car

\Delta v = -10 m/s is the change in velocity of the car

Solving the equation for F,

F=\frac{m \Delta v}{\Delta t}=\frac{(1000 kg)(-10 m/s)}{5 s}=-2000 N

5 0
4 years ago
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