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chubhunter [2.5K]
3 years ago
8

Find the sum of 7a^3+14a+12 and -6a^3+12a^2-7

Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

a³+2a³+5

Step-by-step explanation:

7a³+14a+12+{-6a³}+12a²-7

=<u>7a³-6a³</u>+<u>14a+12a²</u>+<u>12-7</u>

=a³+2a³+5

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Does anyone know how to solve a system of linear equations using elimination? I am having a hard time on how to do it for differ
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1. Multiply each equation so they end up with the same coefficient

2. Subtract your second equation from the first

3. Solve for one of the variables (I tend to solve an equation that only contains 2 variables if possible. So it would be if you have one question with x and y, solve for the easier one)

4. Substitute the variable you found in the least step into one of the other equations and find a second variable.

5. Substitute both variables you found into the last equation and there you should be left with x, y, and z :))

I hope this helped sksjsk if it didn’t I could write it out to hopefully help more :)
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F-7/g=h solve for f <br> What are the steps to solve for f?
nexus9112 [7]

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Rey was planning a party and made a candy bowl with 4 Snickers bars, 2 Hersey’s bar, and 5 Twix bars.
quester [9]

Step-by-step explanation:

a /100%

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3 years ago
What is the value of sin(x) when x = 30°?
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I hope this helps you




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8 0
3 years ago
A physician wants to develop criteria for determining whether a patient's pulse rate is atypical, and she wants to determine whe
valkas [14]

Answer:

a) 66.1 < μ < 82.7

b) 71.9 < μ < 97.7

c) D. No, because the two confidence intervals overlap, we cannot conclude that the two population means are different.

Step-by-step explanation:

Confidence interval is given by the formula

M±t×(\frac{s}{\sqrt{N} }) where

  • M is the sample mean
  • t is the corresponding t value for 95 confidence level
  • s is the sample standard deviation
  • N is the sample size

<u>a. Construct a 95% confidence interval estimate of the mean pulse rate for males.</u>

For men:

M=74.4 t=2.262 s=11.6207 N=10 then confidence interval is:

74.4±2.262×(\frac{11.6207}{\sqrt{10 } }) ≈ 74.4±8.3

<u>b. Construct a 95% confidence interval estimate of the mean pulse rate for females.</u>

For women:

M=84.8 t=2.262 s=18.0488 N=10 then confidence interval is:

84.8±2.262×(\frac{18.0488 }{\sqrt{10 } }) ≈ 84.8±12.9

<u>c. Compare the preceding results. Can we conclude that the population means for males and females are different?</u>

Difference of Population means for males and females are not statistically significant, since confidence intervals overlap.

<u />

4 0
3 years ago
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