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Elanso [62]
2 years ago
6

Can someone please help me with this? I’m really confused on it.

Mathematics
1 answer:
trasher [3.6K]2 years ago
8 0
For this problem you need to put the x values in for x in the equation. For example, put -10 in for x and calculate y, which is g(x)
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Work out the value of a and b in the identity.<br> 3ax + 6 - 4(x + b)= 11x + 14
Levart [38]

Answer:

a=5, b=-2

Step-by-step explanation:

If you simplify the equation, you get:

3ax +6 -4x -4b - 11x - 14 = 0 =>

3ax - 15x -4b -8 = 0

group together x's and constants:

(3a-15)x -8 -4b = 0

To make this 0 for all x, we have to find an a such that 3a-15 = 0 and b such that -8-4b = 0. this leads to a=5, b=-2

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Sav [38]

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Step-by-step explanation:

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3 years ago
Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to
polet [3.4K]
This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 (14 x^{2}) by changing the 14 to 0. That way we'll left with f(x)=5x-1 which only has one real root:
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3 years ago
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Help please and thanks
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Answer:

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Step-by-step explanation:

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3 years ago
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